Please please please helppppppppp

Mathematics

1 answer:

notka56 [123]2 years ago

6 0

Answer:

Step-by-step explanation:

She added 3x and -2x, getting 5x, instead of x. She needs to pay more attention to the positive/negative signs.

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Type the slope-intercept equation

natulia [17]

Answer:

y= -2x +1

Step-by-step explanation:

<u>slope- intercept form</u><u>:</u>

y= mx +c, where m us the gradient and c is the y-intercept.

Let's find the value of m first using the gradient formula.

Gradient= $\frac{y1 - y2}{x1 - x2}$

$m = \frac{ - 3 - 3}{2 - ( - 1)} \\ m = \frac{ - 6}{2 + 1} \\ m = \frac{ - 6}{3} \\ m = - 2$

y= -2x +c

To find the value of c, substitute a pair of coordinates.

When x= -1, y=3,

3= -2(-1) +c

3= 2 +c

c= 3 -2

c= 1

Thus the equation of the line is y= -2x +1.

4 0

2 years ago

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Amanda [17]

Answer:

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Step-by-step explanation:

3 0

3 years ago

If f(x-3)=x^2-4x+5, what's f(1-x)

olganol [36]

Answer:

$\large\boxed{f(1-x)=x^2-4x+5}$

Step-by-step explanation:

$f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2$