The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for 
is 9.
Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and 
for 8<t<11.
A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.
B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.
C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.
D) In this we have to find the function at when m belongs to 
the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.
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Answer:
Width is 2 and Length is 6
Step-by-step explanation:
- As the data is given, the area of a playground is 12 square yards.
- The length of the playground is 3 times longer than its width.
- Let width is x, length is 3 times therefore, length = 3x
As we know the formula for area,
So by putting values in this formula,
=> 3x2 = 12
=> x2 = 12/3,
=> x2 = 4 ,
by taking square root we get x= 2,
- the width is 2 and length is 3 times hence, length is 3(2) = 6.
Answer:
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Answer:
width = 3.5 m
length = 18 m
Step-by-step explanation:
area = length x width
x is the width then length = 2x + 11
x(2x + 11) = 63
2x^2 + 11x - 63 = 0
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
with a = 2
b = 11
c = -63
substitute in the formula
x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)
x = [-11 +/- √(121 + 504)]/4
x = [-11 +/- √625]/4
x = (-11 +/- 25)/4
x1 = (-11 + 25)/4 = 14/4 = 3.5
x2 = (-11 - 25)/4 = -36/4 = -9
since width can't be a negative number, x is 3.5
length = 2x + 11 = 2(3.5) + 11 = 18
5-3+10+137 10 and 137 are your numbers hope this helped
