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irga5000 [103]
3 years ago
9

Find the number of occurrences

Mathematics
1 answer:
Natalka [10]3 years ago
6 0

Some definitions - note that the "bi-" frequencies are a bit ambiguous:

• Weekly = 1/week, i.e. something is done once every week

• Biweekly = 1/(2 weeks)

• Quarterly = 1/(3 months)

• Semimonthly = 2/month

• Bimonthly =  1/(2 months)

• Annually = 1/year

• Monthly = 1/month

"Biweekly" is sometimes used to mean "twice per week", but I've looked up "semimonthly" and it seems to strictly mean "once per half-month" or "twice per month". So to avoid ambiguity, I'll take "bimonthly" and "biweekly" to mean "once every two months" and "once every two weeks".

Some conversion factors:

• 1 year = 12 months = 52 weeks

1. Weekly for 1 year:

1/week • 52 weeks = 52 times

2. Biweekly for 2 years:

1/(2 weeks) • 104 weeks = 52 times

3. Quarterly for 4 years:

1/(3 months) • 48 months = 16 times

4. Semimonthly for 1 year:

2/month • 12 months = 24 times

5. Bimonthly for 2 years:

1/(2 months) • 24 months = 12 times

6. Annually for 25 years:

1/year • 25 years = 25 times

7. Monthly for 1/2 year:

1/month • 6 months = 6 times

8. Weekly for 1.5 years:

1/week • 78 weeks = 78 times

9. Semimonthly for 2.5 years:

2/month • 30 months = 60 times

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6 full episodes

Step-by-step explanation:

You will need to convert 2.5 hours to minutes and divide by 24. Round to the nearest whole number.

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2 years ago
The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
3 years ago
Can someone please answer this with step by step i really need help thank you
Gre4nikov [31]

Answer:

40°

I hope it will be useful.

Step-by-step explanation:

Angles on the same side of the transversal are equal.

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If 25% of a number is 100, what is the number?
Mkey [24]

Answer:

OE. 400

Step-by-step explanation:

.25*400=100

(If you don't believe me, do it out.)

<em><u>Hope this helps!!!</u></em>

<em><u>Brady</u></em>

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Write a basic counting principle problem that has an answer of 24 choices. You write the word problem
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Answer:

Step-by-step explanation:

Lunch has 3 choices for the main dish, chicken, taco, or hamburger, 2 choices for side dish, fries or salad, and 4 choices for beverage, milk, chocolate milk, juice, or water. How many lunches are possible?

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