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irga5000 [103]
3 years ago
9

Find the number of occurrences

Mathematics
1 answer:
Natalka [10]3 years ago
6 0

Some definitions - note that the "bi-" frequencies are a bit ambiguous:

• Weekly = 1/week, i.e. something is done once every week

• Biweekly = 1/(2 weeks)

• Quarterly = 1/(3 months)

• Semimonthly = 2/month

• Bimonthly =  1/(2 months)

• Annually = 1/year

• Monthly = 1/month

"Biweekly" is sometimes used to mean "twice per week", but I've looked up "semimonthly" and it seems to strictly mean "once per half-month" or "twice per month". So to avoid ambiguity, I'll take "bimonthly" and "biweekly" to mean "once every two months" and "once every two weeks".

Some conversion factors:

• 1 year = 12 months = 52 weeks

1. Weekly for 1 year:

1/week • 52 weeks = 52 times

2. Biweekly for 2 years:

1/(2 weeks) • 104 weeks = 52 times

3. Quarterly for 4 years:

1/(3 months) • 48 months = 16 times

4. Semimonthly for 1 year:

2/month • 12 months = 24 times

5. Bimonthly for 2 years:

1/(2 months) • 24 months = 12 times

6. Annually for 25 years:

1/year • 25 years = 25 times

7. Monthly for 1/2 year:

1/month • 6 months = 6 times

8. Weekly for 1.5 years:

1/week • 78 weeks = 78 times

9. Semimonthly for 2.5 years:

2/month • 30 months = 60 times

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Which expression is equivalent to x^4 • x^−2? <br> (A)x^−8 <br> (B)x^2 <br> (C)x^6 <br> (D)-8 • x
Juli2301 [7.4K]

Answer:

B

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} ⇔ a^{(m+n)}

Given

x^{4} × x^{-2} = x^{(4-2)} = x² → B

7 0
3 years ago
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Cameron is designing a calendar as a fund raising project for math class. The cost of printing is $500, plus $2.50 per calendar.
belka [17]
Y = 2.5x - 500

I simplified it a bit, you could write it as y = 5x - 2.5x - 500
3 0
4 years ago
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20% of _____ is 18<br><br> what is the blank
ruslelena [56]

Answer:

90

Step-by-step explanation:

6 0
3 years ago
Name the property the equation illustrates 7+(4+4)=(7+4)+4
attashe74 [19]

the associative property of addition. Try and memorize the different properties. youll need to know them later on. I hope this helped!

6 0
3 years ago
a car covered a certain distance at the speed of 24mph. while returning, the car covered he same distance witht eh spped of 16mp
Mkey [24]

Answer:

19.2

Step-by-step explanation:

You have to trust me, this answer is correct. But here's my solution:

With the formula

Distance=Speed multiplied by Time, we can infer that Speed=Distance/Time.

But we only have one variable (Speed) in the two we need (Speed and Time), we have to pretend we have both variables. You can put the time as 1 hour because that's the most basic unit. Note that this strategy will also work with 2 hours, 3 hours, or any measure of time.

So now for distance, let's see how fast a car can travel 24 miles. When going at 24 mph, then it'll take 1 hour. With 16 mph, then it'll take 1 hour and 30 minutes, so 1.5 or 3/2 hours.  

Now we have the distance, which is 2 times 24 (Because the 24 mph and 16 mph both traveled 24 miles), equaling 48, and time, which is 1 hour plus 1.5 hours, which is 2.5 hours.

Now we use the formula Speed=Distance/Time, with 48/2.5=19 1/5 or 19.2

DUBS

(Please consider giving a Brainliest. I spent lots of time on this, and it's honestly the best answer out of all!)

8 0
3 years ago
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