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Marianna [84]
3 years ago
6

GIVING BRAINLIEST PLS HELP

Mathematics
2 answers:
baherus [9]3 years ago
7 0

Hi! Your answer is x - 5

Please see an explanation for a better and clear understanding to your problem!

Any questions about my answer and explanation can be asked through comments! :)

Step-by-step explanation:

To find an expression that is a factor, we simply factor the expression first. Sound a bit confusing? Well It's not that confusing if you understand it.

So what we need to do is to factor the expression first.

\huge{x^3-2x^2-15x}

Notice anything? Yes, the whole expression has x-term as a variable. We can simply factor the expression by common factor, pulling the variable with the least degree.

We should get \large{x(x^2-2x-15)} from common factor. However, we can still factor inside the brackets. Inside the bracket, the expression can be factored by two brackets factor. Our x-term which is outside of bracket is a bit useless so you can ignore it. What we want is to factor the expression inside the bracket.

\large{x^2-2x-15}

To factor this kind of expression, we use two brackets factoring for a = 1.

\large{(x-a)(x-b)}

To find the first term, we simply multiply x and x to each others.

To find the second term, we add -bx and -ax to each others.

To find the first term, we multiply -a and -b to each others.

So if we follow these steps, our (x-a)(x-b) should be x²-ax-bx+ab = x²-(a+b)x+ab

\large{x^2-(a+b)x+ab}

We only need to find a and b value. Which two numbers multiplying each others and get -15? There are only -5 and 3 or 3 and -5.

That means -5 and 3 | 3 and -5 are our only options.

But what two numbers adding up each others and get -2? That means it's -5 and 3 because -5+3 = -2.

Therefore, from x²-2x-15. Our factors are (x-5)(x+3)

So when the expression is completely factored, the new factored expression is x(x-5)(x+3) Then we look at the choices to see if there are these factors in the choices. From the choices and the expression, the only correct answer is (x-5) because x+5 is not a factor (it doesn't appear), same with other two choices. They seem to be factored but not fully factored.

Hence, the answer is x - 5

creativ13 [48]3 years ago
6 0

Answer:

A) x-5

Step-by-step explanation:

(x-5)(x^2+3x) = x^3-2x^2 -15

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2 years ago
15pts please help asap<br> 2.5 as an improper fraction?
RideAnS [48]
2.5 = 2 5/10 as a Mixed fraction

To get a improper fraction, multiply the whole number with the denominator, and then add the numerator to the answer, giving the numerator (keep the denominator number)

2 x 10 = 20
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25/10 is your answer

hope this helps
6 0
3 years ago
What is 6/10 rounded to the nearest half
belka [17]

6/10 rounding to the nearest half would be 1, not 0.

Reason for this: Here is a number line to help you!

|----|----|

Left line = 0

Middle line = 1/2

Right line = 1

Here is another rule!

0/10, 1/10, 2/10, 3/10, 4/10 = rounded to the nearest half would be 0

5/10, 6/10, 7/10, 8/10, 9/10, 10/10 = rounded to the nearest half would be 1.

So 6/10 rounded to the nearest half is 1.

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5 0
3 years ago
Fill in the blank with a constant, so that the resulting quadratic expression is the square of a binomial. $\[x^2 + 22x + \under
saw5 [17]

Answer:

$\[x^2 + 22x + 121\]$

Step-by-step explanation:

Given

$\[x^2 + 22x + \underline{~~~~}.\]$

Required

Fill in the gap

Represent the blank with k

$\[x^2 + 22x + k\]$

Solving for k...

To do this, we start by getting the coefficient of x

Coefficient of x = 22

<em />

Divide the coefficient by 2

Result = 22/2

Result = 11

Take the square of this result, to give k

k= 11^2

k= 121

Substitute 121 for k

$\[x^2 + 22x + 121\]$

The expression can be factorized as follows;

x^2 + 11x + 11x + 121

x(x + 11)+11(x+11)

(x+11)(x+11)

(x+11)^2

<em>Hence, the quadratic expression is </em>$\[x^2 + 22x + 121\]$<em></em>

8 0
3 years ago
Read 2 more answers
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