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murzikaleks [220]
3 years ago
9

Help please i dont no

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
3 0
The answer would be 24 glasses because you do 8 x 3 and you get 24
PIT_PIT [208]3 years ago
3 0

Answer:

24

Step-by-step explanation:

8x3

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Find the value of B in the following equation if you know it goes through the point (-5, -8):
MA_775_DIABLO [31]
86? I'm not sure, sorry.

I plugged in the x and y values of the point given
5 0
3 years ago
How to answer this problem solving question: Anita and Terry ride the subway on sundays to visit their grandparents. There are 2
Dovator [93]
We know that they have:
2 entrences
3 ways to chose (escalator,elevator and stairs)
8 gates
and again 3 ways to chose (escalator, elevator and stairway)

now you have to multiply it:
2*3*8*3=6*8*3=48*3=144

There are 144 different ways that Anita and Terry can go from street level to the trains:)
4 0
3 years ago
Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

6 0
2 years ago
Identify the 34th term of the arithmetic sequence 2, 7, 12
torisob [31]
The equation is AN=A1+D(N-1) A1 being the first number (2) D being the difference (in this case 5) and N being the nth term to find (34) so here you have AN=2+5(34-1) then AN=2+5(33). the answer here is 167.
5 0
3 years ago
Jasmin, Quinn, and Maddy are rock climbing. Jasmin is 42 ½ feet below Quinn. Maddy is 67 ¾ feet above Jasmin. What is Maddy's po
ladessa [460]

Answer:

25\frac{1}{4} feet

<em />

Step-by-step explanation:

Given

Maddy = 67\frac{3}{4} above Jasmin

Jasmin = 42\frac{1}{2} below Quinn

Required

Determine Maddy's position relative to Quinn's

From the given parameter, one can easily deduce that Quinn is in between Maddy and Jasmin (See attachment)

Using the attachment as a point of reference;

z = 67\frac{3}{4}

x = 42\frac{1}{2}

The relationship between x, y and z is

z = y + x

Make y the subject of formula

y = z - x

Substitute the values of z and x

y = 67\frac{3}{4} - 42\frac{1}{2}

Convert to improper fractions

y = \frac{271}{4} - \frac{85}{2}

Take LCM

y = \frac{271 - 170}{4}

y = \frac{101}{4}

y = 25\frac{1}{4}

<em>Hence; Maddy's position relative to Quinn's is </em>25\frac{1}{4}<em> feet</em>

8 0
3 years ago
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