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AfilCa [17]
2 years ago
12

Graph your linear equation. y=x÷3​

Mathematics
1 answer:
mojhsa [17]2 years ago
7 0
Here ya go
(correct me if wrong)

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Find the distance d (P1,P2) between the given points P1 and P2 P1= (5,4) P2=(-4,5)
oee [108]

Answer:

\sqrt{82  }

Step-by-step explanation:

d = \sqrt{(x_{1} - x_2)^2+(y_1-y_2)^2  }

d = \sqrt{(5 - (-4))^2+(4-5)^2  }

d = \sqrt{(9)^2+(-1)^2  }

d = \sqrt{81+1  } = \sqrt{82  }

5 0
3 years ago
How do I convert the letter in an answered equation into a number, for example the answer 8.50246E6
Pie

Answer:

1Step-by-step explanation:

1 + IS 1 AND ITS 1

6 0
2 years ago
Read 2 more answers
Complete the paragraph to show how you can solve problems involving equivalent expressions.
miv72 [106K]

Answer:

Step-by-step explanation:

Model the expressions

with bar models or algebra tiles to determine if the expressions are

Equivalent.

You can also write equivalent expressions using

properties of operations

and order of operations.

8 0
3 years ago
Read 2 more answers
The population of a certain species of fish has a relative growth rate of 1.1% per year. It is estimated that the population in
Juliette [100K]

Answer:

(a) n(t) = P(0)*e^(0.010939940t)

(b) 12,674,681 (nearest unit)

(c) 14 years (nearest year)

Step-by-step explanation:

rate = 1.1% / year = 1.011

(a)

P(0) = 12,000,000  = population in 2010

In compound interest format, after t years

P(t) = P(0)* (1.011)^t

Given format = P(0)* e^(rt)

therefore

e^(rt) = 1.011^t       use law of exponents

(e^r)^t = 1.011^t

e^r = 1.011

r = log_e(1.011) = 0.010939940   (to 9 decimal places)

required formula is

n(t) = P(0)*e^(0.010939940t)

(b)

in 2015,

P(0)=12000000, n = 5 (years after 2010)

n(5) = 12000000*e^( 0.010939940 * 5 ) = 12,674,680.6 = 12,674,681 (nearest unit)

(c)

to reach 14 million, we equate

n(t) = 14,000,000

12,000,000 *e^(0.010939940*t) = 14,000,000

e^(0.010939940*t) = 14000000/12000000 = 7/6

take log on both sides

0.010939940*t = log(7/6)

t = log(7/6) / 0.010939940 = 14.091 years = 14 years to the nearest year.

See graph attached.  Y-axis is in millions, x-axis is in years.

4 0
3 years ago
if your car gets 26 miles per gallon how much does it cost to drive 420 miles when gas is $2.80 per gallon​
Kitty [74]

Answer:

$45.22

Step-by-step explanation:

The number of miles per gallon can be represented by the ratio:

\frac{miles}{gallon}=\frac{26}{1}

Since we know the unit rate of 26 miles per gallon of gas, we can set up a proportion, or equivalent ratios, to find the number of gallons needed for 420 miles:

\frac{26}{1}=\frac{420}{x}, where 'x' is the number of gallons of gas

cross-multiply and divide:  26x = 420 or x ≈ 16.15 gallons

If gas is $2.80 per gallon, take the total number of gallons needed and multiply by $2.80:

16.15 x $2.80 = $45.22

5 0
3 years ago
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