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3 years ago

PLEASE HELP!! HURRY!! THIS IS WAYY PAST DUE!! DON'T ANSWER FOR POINTS!! I NEED HELP!!!

Mathematics

1 answer:

kolbaska11 [484]3 years ago

7 0

Answer:

Based on your line, what is the likely test score of a student who does not study for the test? 45

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If Casey deposits $16 into his lunch account each week, how much will be deposited in 5 weeks? If Casey decides to buy lunch for

Ivanshal [37]

Answer:

The exact number would be 26.66666667 but it would be 26.

Step-by-step explanation:

Usually when dealing with decimals anything 5 and up would be rounded up but since we are dealing with money we don't round up. Since his friends lunch cost $3 every lunch the most he will be able to buy is 26. He will have about $2.5 left over which he cannot buy a lunch with so thats why you dont round up.

8 0

3 years ago

1. (5,8) m= 3<br> It wants me to write this in slope intercept form

ikadub [295]

Answer:

The answer is: y = 3x - 7

Step-by-step explanation:

Given point: (5, 8).

Slope m = 3

Use the point slope form and solve for y:

y - y1 = m(x - x1)

y - 8 = 3(x - 5)

y - 8 = 3x - 15

y = 3x - 15 + 8

y = 3x - 7

Proof:

f(x) = 3x - 7

f(5) = 3(5) - 7

= 15 - 7 = 8, giving (5, 8)

3 0

3 years ago

Read 2 more answers

Hiking

Nata [24]

Answer:

I’m sorry but I don’t understand the question

Step-by-step explanation:

3 0

2 years ago

The contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces. We are interested in testing to d

NikAS [45]

Answer:

Option b. should not be rejected

Step-by-step explanation:

We are given that the contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces.

We have to test whether the variance of the population is significantly more than 0.003, i.e.;

Null Hypothesis, $H_0$ : $\sigma$ = $\sqrt{0.003}$

Alternate Hypothesis, $H_1$ : $\sigma > \sqrt{0.003}$

The test statistics used here for testing variance is;

T.S. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 0.06

n = sample size = 26 cans

So, Test statistics = $\frac{(26-1)0.06^{2} }{0.003 }$ ~ $\chi^{2}__2_5$

= 30

So, at 5% level of significance chi square table gives critical value of 37.65 at 25 degree of freedom. Since our test statistics is less than the critical so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that null hypothesis should not be rejected and variance of population is 0.003.

5 0

3 years ago

The lenghts of two sides of. a triangle are 12cm and 15cm.between what two measures should be the length of the third side fall?

maw [93]

Answer:

Step-by-step explanation:

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2 years ago