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lana66690 [7]
3 years ago
10

PLEASE HELP!! HURRY!! THIS IS WAYY PAST DUE!! DON'T ANSWER FOR POINTS!! I NEED HELP!!!

Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0

Answer:

Based on your line, what is the likely test score of a student who does not study for the test? 45

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If x+4/4 = y+7/7 then x/4=___
muminat
Please, enclose those binomials x+4 and y+7 inside parentheses:

(x+4) / 4 = (y+7) / 7.  Find (x/4).

Let's solve the above equation for x:

x+4 = 4(y+7)/7.  Then x = 4(y+7) / 7   -   4

Last, divide all 3 terms by 4:            x/4 = (y+7) / 7 - 1   (answer)
                                                         
                                                      y + 7 - 7
You could also type this as x/4 = ------------- = y/7
                                                           7
4 0
3 years ago
Find the Derivative.<br> f(x) = -xcos3x
DENIUS [597]

Answer:

\frac{d}{dx}(-xcos3x)=  3x \ sin(3x)- cos(3x)

Step-by-step explanation:

Use the Product Rule for derivatives, which states that:

  • \frac{d}{dx} =[f(x)g(x)]= f(x)g'(x)+f'(x)g(x)

In the function we are given, f(x)=-x \cos3x, we can break it up into two factors: -x is being multiplied by cos3x.

Now, we have the factors:

  • -x \\   $cos 3x

Before using the product rule, let's find the derivative of cos3x using the chain rule and the power rule.

  • \frac{d}{dx}(cos3x)= \frac{d}{dx} (cos3x) \times \frac{d}{dx} (3x) \\ \frac{d}{dx}(cos3x)= (-sin3x) \times 3 \\ \frac{d}{dx} (cos3x) = -3sin(3x)

Now let's apply the product rule to f(x) = -xcos3x.

  • \frac{d}{dx}(-xcos3x)=  (-x)(-3sin3x) + (-1)(cos3x)

Simplify this equation.

  • \frac{d}{dx}(-xcos3x)=  (x)(3sin3x) - (cos3x)

Multiply x and 3 together and remove the parentheses.

  • \frac{d}{dx}(-xcos3x)=  3x \ sin(3x)- cos(3x)

Therefore, this is the derivative of the function f(x)=-xcos3x.

3 0
3 years ago
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How do i find the missing length indicated
SCORPION-xisa [38]

Answer:

The Pythagorean theorem states that a2 + b2 = c2 in a right triangle where c is the longest side. You can use this equation to figure out the length of one side if you have the lengths of the other two. The figure shows two right triangles that are each missing one side's measure.

Step-by-step explanation:

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Solve for A<br><br> Thank u so much !
lianna [129]

Answer:

\huge\boxed{A=4d^2+4h}

Step-by-step explanation:

\dfrac{1}{4}A-h=d^2\qquad\text{add}\ h\ \text{to both sides}\\\\\dfrac{1}{4}A-h+h=d^2+h\\\\\dfrac{1}{4}A=d^2+h\qquad\text{multiply both sides by 4}\\\\4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1}A=4d^2+4h\\\\A=4d^2+4h

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3 years ago
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Answer:

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