Sub those points for x
f(x) is the y
(x,y)
so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint
for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point
for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point
points are
(0,3)
(1,5)
(2,35)
Answer:
Step-by-step explanation:
To solve this problem we need to write the mixed fraction as a fractional number, as follows:
Then, evaluating the expression:
× = =
Answer:
4536363646
Step-by-step explanation: