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Inga [223]
3 years ago
7

Solve for x. 112° (5x - 3)° (4x + 16)°

Mathematics
2 answers:
ANTONII [103]3 years ago
8 0

Answer:

11

Step-by-step explanation:

180 - 112 = 68

4x + 16 +5x - 3 + 68 = 180

simplify.

9x + 81 = 180. subtract 81 from 180

9x = 99. divide 99 by 9

x = 11.

Tems11 [23]3 years ago
6 0
To find x add the two interior angles together and put them equal to 112 (the exterior angle).

ANSWER: 109/9
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3 years ago
Which statement BEST describes the growth of bacteria modeled by the function f(x)=1.8x
lara [203]

Answer:


Step-by-step explanation:

f(x) = 1.8x is a linear function and does not model the growth of bacteria.  Perhaps you meant f(x) = 1.8^x, which is an exponential function whose initial value is 1.  Please ensure that you have copied down this problem exactly as it was presented.



6 0
3 years ago
Please help me I havent found answers any where and dont know how to do this. Help me please. I have posted this once and it see
Tems11 [23]
This is the answer for your question

4 0
3 years ago
A mother gives birth to a 9 pound baby. every 4 months, the baby gained 2 pounds. if x is the age of the baby in months, then y
chubhunter [2.5K]
For the equation of the line of the form y = mx + b, m is the slope of the line and b is the y-intercept which is the value of y when x is equal to zero. The slope is the rate of change of y per change in x. "y" would represent the dependent variable which is the weight of the baby while "x" represents the independent variable which is the number of months or the age of the baby in months. We calculate the slope as follows:

slope = (11 - 9) / ( 4 - 0) = 2/4 = 0.5
at x = 0, it is said that the weight of the baby is 9 lbs so the value of b would be 9.

The equation of the line would be y = 0.5x + 9
6 0
4 years ago
I need help! (HAPPY MLK DAY!!!)
olga2289 [7]

The slope and length of the given sides of the quadrilateral can be

found by using the coordinates of the vertices.

Correct responses:

  • Slope \ of \ \overline{IJ} = \underline{-\dfrac{7}{6} },      Length of \overline{IJ} = \underline{\sqrt{85} }
  • Slope \ of \ \overline{JK} = \underline {-\dfrac{2}{9}},     Length of \overline{JK} = \underline{\sqrt{85} }
  • Slope \ of \ \overline{KL} = \underline{-\dfrac{7}{6} },      Length of \overline{KL} = \underline{\sqrt{85}}
  • Slope \ of \  \overline{LI} = \underline{ -\dfrac{2}{9} },        Length of \overline{LI} = \underline{\sqrt{85} }

<h3>Methods used to find the slope and length of a line</h3>

The given coordinates of the vertices are;

K(-7, 0), J(2, -2), I(8, -9), L(-1, -7)

  • Slope = \mathbf{\dfrac{y_2 - y_1}{x_2 - x_1}}

  • Length \ of \ line =  \mathbf{ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}

Therefore;

Slope \ of \ \mathbf{\overline{IJ}} = \dfrac{-2 - (-9)}{2 - 8} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length \ of \ \mathbf{\overline{IJ}} = \sqrt{(2 - 8)^2 + (-2 - (-9))^2} = \underline{\sqrt{85}}

Slope \  of \ \mathbf{\overline{JK}} = \dfrac{0 - (-2)}{-7 - 2}  = \dfrac{2}{-9} = \underline{-\dfrac{2}{9}}

Length \ of \ \mathbf{\overline{JK}} = \sqrt{(-7 - 2)^2 + (0 - (-2))^2}  = \underline{ \sqrt{85}}

Slope \ of \ \mathbf{\overline{KL}} = \dfrac{0 - (-7)}{-7 - (-1)} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}

Length  \ of \ \mathbf{\overline{KL} }= \sqrt{(-7 - (-1))^2 + (0 - (-7))^2} =\underline{ \sqrt{85}}

Slope \ of \ \mathbf{\overline{LI}} = \dfrac{(-9 - (-7))}{(8 - (-1))} = \dfrac{-2}{9} = \underline{-\dfrac{2}{9}}

Length \ of \ \mathbf{\overline{LI}} = \sqrt{(8 - (-1))^2 + (-9 - (-7))^2} = \underline{\sqrt{85}}

Learn more about finding the slope and length of a line here:

brainly.com/question/11612395

brainly.com/question/14039630

5 0
3 years ago
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