18 and 35. The numbers whose sum 53 are 18 and 35.
The key to solve this problem is using a system of equations.
There are two numbers whose sum is 53. This number can be represented as x and y. So:
x + y = 53
Three times the smaller number is equal to 19 more than the larger. Let's set x as the smaller number and y the larger number. So:
3x = 19 + y
Clear y in both equations and let's use the equalization method to solve for x:
y = 53 - x and y = 3x - 19
Then,
53 - x = 3x - 19
53 + 19 = 3x + x ---------> 3x + x = 53 + 19 -------> 4x = 72
x = 72/4 = 18
To find y, let's substitute x = 18 in the equation x + y = 53
18 + y = 53 --------> y = 53 - 18
y = 35
Answer:
This appears to be in another language.
Step-by-step explanation:
Ajutatima va rog, first and foremost is simply nonsense in the English language.
Answer:
It would take 5.9 years to the nearest tenth of a year
Step-by-step explanation:
The formula of the compound continuously interest is A = P , where
- A is the value of the account in t years
- P is the principal initially invested
- e is the base of a natural logarithm
- r is the rate of interest in decimal
∵ Serenity invested $2,400 in an account
∴ P = 2400
∵ The account paying an interest rate of 3.4%, compounded continuously
∴ r = 3.4% ⇒ divide it by 100 to change it to decimal
∴ r = 3.4 ÷ 100 = 0.034
∵ The value of the account reached to $2,930
∴ A = 2930
→ Substitute these values in the formula above to find t
∵ 2930 = 2400
→ Divide both sides by 2400
∴ =
→ Insert ㏑ in both sides
∴ ㏑() = ㏑()
→ Remember ㏑() = n
∴ ㏑() = 0.034t
→ Divide both sides by 0.034 to find t
∴ 5.868637814 = t
→ Round it to the nearest tenth of a year
∴ t = 5.9 years
∴ It would take 5.9 years to the nearest tenth of a year
2.5 and 5 should be the answer