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Vinil7 [7]
3 years ago
11

Please show your work and help

Mathematics
1 answer:
Levart [38]3 years ago
8 0

Answer:

22.5 cm

Step-by-step explanation:

An equilateral triangle has 3 equal sides

perimeter is the sum of all 3 sides, hence

perimeter = 3 × 7.5 = 22.5 cm


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Hi everyone can someone help me out with this question please
luda_lava [24]
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and x stands for the number of years.
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3 years ago
Which of the following functions is graphed below?
Pie

Answer:

C

Step-by-step explanation:

C is the solution

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Consider a steel ball floating on the surface of mercury in a half-filled container. What happens when the rest of the container
Helen [10]

Answer

The steel ball will be caught up in between the mercury and water medium.

Step-by-step explanation:

  • Mercury with a density of 13546 kg/m^3
  • water with a density of 1000 kg/m^3
  • Steel with a density of 8050 kg/m^3

From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.

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8 0
3 years ago
What is the surface area of the cylinder with height 7 cm and radius 5 cm? Round
nalin [4]

Answer:

376.991 cm²

Step-by-step explanation:

SA_{cylinder} = 2\pi r^{2}  + 2\pi rh

Surface Area = 2π(5²) + 2π(5)(7)

                      = 50π + 70π

                      = 120π

                      = 376.9911184... ≈ 376.991

<h2>Derive Surface Area of A Cylinder</h2>

If you take a look at a net of a cylinder, you can see it is composed of two circles(bases) and a rectangular strip with the length of the diameter of the circle

The formula for the area of a circle = πr², and since there are 2, it is 2πr²

The formula for circumference of a circle = 2πr, and since we are multiplying that by the height by the height of the cylinder, it is 2πrh

∴ 2πr² + 2πrh

5 0
3 years ago
Which system of equations has no solutions?
baherus [9]

Answer:

A

Step-by-step explanation:the lines do not cross therefor the two equations do not share a solution.

5 0
3 years ago
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