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Semmy [17]
3 years ago
10

When you reflect a point over the x-axis you negate the y value. True False

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

True.

Step-by-step explanation:

The rule for reflecting the X value is to negate the Y value but leave the X as it is.

Example: K= (7,2) when reflected it would be (7,-2).

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Find the slope of line a and line b from two points
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Answer: Line A has a slope of 3/4 and Line B has a slope of 5/6

Step-by-step explanation: Look at the attachment

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2 years ago
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Two bugs are running back and forth along a straight branch at constant speeds
Annette [7]
It would be 60cm because 40 plus 20 equals 60
3 0
2 years ago
Please help i don’t understand this
swat32

Similar polygons only differ by a scaling factor. In other words, two polygons are similar if one is the scaled version of the other.

In particular, this implies that the angles are preserved, and the correspondent sides are in proportion.

These two polygons are both rectangles, so the angles are preserved. We must check the sides, and we have to check if the smaller sides are in the same proportion as the bigger sides.

So, the two rectangles are similar if the following is true.

4\div 5 = 11\div 12

In any proportion, the product of the inner terms must be the same as the product of the outer terms:

4\cdot 12 = 5\cdot 11 \iff 48=55

This is clearly false, and thus the two rectangles are not similar.

5 0
2 years ago
Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
3 years ago
Can you guy's please help me out I was absent and now I don't have a clue!
Elena-2011 [213]
For these problems you have to use PEMDAS so for problem 15 you would do the parentheses first, (21-3) you get 18 and then exponents, 3^2, you get 9, no multiplication but there is division so take your answers, 18 and 9 and divide them, you get 2, so the answer to 15 is 2.
6 0
3 years ago
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