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Semmy [17]
3 years ago
10

When you reflect a point over the x-axis you negate the y value. True False

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

True.

Step-by-step explanation:

The rule for reflecting the X value is to negate the Y value but leave the X as it is.

Example: K= (7,2) when reflected it would be (7,-2).

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Simplify the expression. (3.5x - 5) + (7.2x + 10)
Mamont248 [21]

Answer:

10.7x + 5

Step-by-step explanation:

(3.5x - 5) + (7.2x + 10)

Take out the parenthesis so it can be easier to see

3.5x - 5 + 7.2x + 10

Combine like terms

(3.5x and 7.2x) and ( -5 and 10)

10.7x + 5

And you cannot simplify it anymore

Hope this helped!

Have a supercalifragilisticexpialidocious day!

8 0
3 years ago
2. Given that set M = {Even numbers between 20 and 35), find n(m)​
Advocard [28]

Step-by-step explanation:

Set M = {20,22,24,26,28,30,32,34}

n(M) = no. of elements in set M

i.e.

n(M) = 8

8 0
3 years ago
Read 2 more answers
What is the answer to 4-7x=5x
Makovka662 [10]
4-7x=5
 +7x +7x
4= 12x
/12  /12

x= 4/12
x= 1/3
3 0
3 years ago
A cubical tank of edge 12 cm is half filled with water. The water is poured into an empty rectangular tank measuring 10 cm by 8
qaws [65]

Answer:

3040000mm³

Step-by-step explanation:

Volume of a cube = a³ ; a = size of edge

Volume of cubical tank = 12³ = 12 * 12 * 12 = 1728 cm³

Half filled cube = 1728 / 2 = 864 cm³

Volume is f rectangular tank :

V = length * width * height

V = 10 * 8 * 7 = 560 cm³

Volume of water left in cubical tank :

(864 - 560) = 304cm³

1cm³ = 1000mm³

304cm³ = 304 * 1000 = 3040000mm³

3 0
3 years ago
Find the surface area of a pyramid with a square base with dimensions 100 mm by 100 mm and height of 75 mm.
Reil [10]

To solve for the surface area of the pyramid, we make use of the formula:

A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))

where,

l and w are the base of the pyramid = 100 mm

h is the height of the pyramid = 75 mm

 

Substituting the given values into the equation:

A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100 / 2)^2 + 75^2))

A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)

A = 20,148.90 mm^2

 

Therefore the surface area of the pyramid is about 20,149 mm^2.

8 0
3 years ago
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