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shtirl [24]
3 years ago
9

The ratio of dogs to cats in a zoo choir is 4 : 3. There are 6 more dogs than cats. If another 2 cats join the choir, what will

be the new ratio of dogs to cats?
Mathematics
1 answer:
Fofino [41]3 years ago
4 0

Answer:

6:5

Step-by-step explanation:

c = number of cats

d = number of dogs

d = c+6

Set up a ratio:

4/3 = d/c

Then replace d with c+6, so your equation only has one variable.

\frac{4}{3} = \frac{c+6}{c}

Cross multiply

4c = 3(c+6)

Multiply everything in the parentheses by 3.

4c = 3c + 18

Subtract 3c from both sides

4c - 3c = 18

c = 18

d = c + 6 = 18 + 6 = 24

If 2 more cats join, then you will have 20 cats and 24 dogs, so the ratio of dogs to cats will now be 24:20.  Divide each side by 4 for a ratio of 6:5.

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What are the solutions to the quadratic equation (5y+6)2=24
yulyashka [42]

The value of y is, y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}

We have given that,

\left(5y+6\right)^2=24

We have to determine the value of y,

<h3>What is the formula for the quadratic equation?</h3>

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

Therefore,we get

5y+6=\sqrt{24}

5y+6=2\sqrt{6}

\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}

5y+6-6=2\sqrt{6}-6

5y=2\sqrt{6}-6

\frac{5y}{5}=\frac{2\sqrt{6}}{5}-\frac{6}{5}

y=\frac{2\sqrt{6}-6}{5}

y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}

Therefore the value of y is,

y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}

To learn more about the quadratic equation visit:

brainly.com/question/1214333

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