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faltersainse [42]
3 years ago
5

What is the solutiom of the equation - 25=x-12​

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0

Answer:

The answer is -13 = x

Step-by-step explanation:

Add 12 on both sides. Which cancels the -12 on the right.

-25+12=-13.

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X÷x+4=3÷x-1<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7Bx%20%2B%204%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7Bx%20-%201%7D%
butalik [34]

\frac{x}{x + 4}=\frac{3}{x - 1} \\3(x+4) = x(x-1)\\3x+12 =x^2-x\\0=x^2-4x-12\\0=(x-6)(x+2)\\X= 6, -2


Steps:

First we cross multiply

Then Distribute,

Then move all terms to one side

Factor

Set each factor equal to zero

6 0
3 years ago
Please help me pls 7tyh grade math
Andrews [41]
(4/7)-(1/3)
(12/31)-(7/21)
(5/21) is left
Or
In decimal form
(4/7)=0.571
(1/3)= 0.333
0.571-0.333
=0.238
8 0
3 years ago
S=a1/1-r
valentinak56 [21]

Answer:

4

Step-by-step explanation:

This is an <em>infinite geometric series</em>. This has a sum of  \frac{a}{1-r}

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

<u />

<u>First term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3

<u>Second term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}

<em>Let's see the common ratio:  \frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}</em>

<em />

<em>Thus we have a = 3 and r = 1/4</em><em>. Plugging into the formula of the infinite sum, we get:</em>

<em>s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4</em>

<em />

<em>So, </em><em>the answer is 4</em>

4 0
3 years ago
5x+5=10 what dose x =
Romashka [77]

Answer:0 becAusethere isno x

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help :( math for 8th
rewona [7]

Answer:

She should add 10x to both sides

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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