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Artist 52 [7]
3 years ago
14

Find the value for the given variables. Give the variables in simplest radical form.

Mathematics
2 answers:
harina [27]3 years ago
5 0

x = 7√3 & y = 14

..................................

Svetach [21]3 years ago
3 0

\huge\boxed{ \boxed{\mathrm{ \underline{Answer}࿐  }}}

The given triangle is a right angled triangle,

so let's apply trigonometry here :

  • \sin(30)   =  \dfrac{7}{y}

  • \dfrac{1}{2}  =  \dfrac{7}{y}

  • y = 7 \times 2

  • y = 14 \:  \: units

Now,

  • \cos(30)  =  \dfrac{x}{y}

  • \dfrac{ \sqrt{3} }{2}  =  \dfrac{x}{14}

  • x =  \dfrac{14 \sqrt{3} }{2}

  • x = 7 \sqrt{3}

  • x = 12.12 \:  \: units

_____________________________

\mathrm{ ☠ \: TeeNForeveR \:☠ }

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A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
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Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

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So, Probability of getting head from fair coin = \dfrac{1}{2}

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Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

5 0
3 years ago
PLEASE HELP 8th GRADE MATH
posledela

Answer:

I'm going to say C

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7 0
3 years ago
Solve -2.5n + 8.7 &gt; 5.45.
AlexFokin [52]
A. n<1.3

-2.5n+8.7>5.45
subtract 8.7 from both sides
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divide -2.5 from both sides 
(since you divided by a negative you flip the sign!!)
n<1.3


5 0
3 years ago
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