The caret (^) is the symbol conventionally used to indicate an exponent.
You have
area = 2.76·10^12
width = 4.6·10^5
You want to find the perimeter of the rectangle with these dimensions.
The perimeter of a rectangle is twice the sum of length and width.
perimeter = 2*(length + width)
The length can be figured from the area using the formula for area.
area = length*width
area/width = length . . . . . . . . . divide by width
Filling in the numbers, we have
perimeter = 2*((2.76·10^12)/(4.6·10^5) +(4.6·10^5))
perimeter = 2*(6.0·10^6 +0.46·10^6)
perimeter = 2*6.46·10^6 = 1.292·10^7
The perimeter of the rectangle is ...
1.292·10^7
Notice that 
for 
implies that 
elsewhere, since
where 
is a random variable representing cable lengths according to the PDF 
.
a. By definition of expectation, the mean is
![E[X]=\displaystyle\int_{-\infty}^\infty x\,f(x)\,\mathrm dx=0.1\int_{1200}^{1210}x\,\mathrm dx=1205](https://tex.z-dn.net/?f=E%5BX%5D%3D%5Cdisplaystyle%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty%20x%5C%2Cf%28x%29%5C%2C%5Cmathrm%20dx%3D0.1%5Cint_%7B1200%7D%5E%7B1210%7Dx%5C%2C%5Cmathrm%20dx%3D1205)
The variance is
![\operatorname{Var}[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2](https://tex.z-dn.net/?f=%5Coperatorname%7BVar%7D%5BX%5D%3DE%5B%28X-E%5BX%5D%29%5E2%5D%3DE%5BX%5E2%5D-E%5BX%5D%5E2)
where
![E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f(x)\,\mathrm dx=0.1\int_{1200}^{1210}x^2\,\mathrm dx=\frac{4,356,100}3](https://tex.z-dn.net/?f=E%5BX%5E2%5D%3D%5Cdisplaystyle%5Cint_%7B-%5Cinfty%7D%5E%5Cinfty%20x%5E2%5C%2Cf%28x%29%5C%2C%5Cmathrm%20dx%3D0.1%5Cint_%7B1200%7D%5E%7B1210%7Dx%5E2%5C%2C%5Cmathrm%20dx%3D%5Cfrac%7B4%2C356%2C100%7D3)
so that the variance is 
, making the standard deviation 
.
b. The proportion of cables within specs is
3x -4 (5 - x) = 7x -20
3x-20+4x=7x-20
7x-20=7x-20
