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IgorLugansk [536]
3 years ago
5

Questio

Mathematics
1 answer:
Olenka [21]3 years ago
4 0

Answer:

  d = -1/3, 0

Step-by-step explanation:

Subtract the constant on the left, take the square root, and solve from there.

  (6d +1)^2 + 12 = 13 . . . . given

  (6d +1)^2 = 1 . . . . . . . . . .subtract 12

  6d +1 = ±√1 . . . . . . . . . . take the square root

  6d = -1 ±1 . . . . . . . . . . . .subtract 1

  d = (-1 ±1)/6 . . . . . . . . . . divide by 6

  d = -1/3, 0

_____

Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:

  f(x) = (6x+1)^ +12 -13

We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.

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