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SOVA2 [1]
3 years ago
8

What is the least common multiple (LCM) of 4 and 15? A. 19 B. 20 C. 60 D. 30

Mathematics
2 answers:
ad-work [718]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Multiples of 4: 4,8,16,20,24,28,32,36,40,44,48,52,56,60

Multiples of 15: 15,30,45,60

Th smallest number that they both can multiply to is 60

vaieri [72.5K]3 years ago
3 0
The least common multiple would be 60
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Simplify: 2{10-5+x[1+3(6-2)]}
REY [17]

Answer:

10+26x

Step-by-step explanation:

To solve this, work your way from the inner most parentheses to the outer most:

  1. The inner most parentheses is around 6-2, meaning you solve this first. When you solve this, you get 4.
  2. The second most inner parentheses is around (1+3 times 4) using PEMDAS, you first solve the multiplication, and then add. Once you solve this, you get 13.
  3. Next, the outer most parentheses is around (10-5+13x). When you simplify this, you get 5+13x
  4. Finally, you multiply 2(5+13x). Using distributive property, you get 10+26x as your final simplified answer.
3 0
3 years ago
For what values of theta (0 less than or equal to theta less than or equal to 2pi) do maximum r values occur on the graph the po
9966 [12]

Answer:

Step-by-step explanation:

To find the values of the angle which makes maximum r you use the derivative of r

\frac{dr}{d\theta}=\frac{1}{3}sin(3\theta)

If you equals this derivative to zero you obtain the value of the angle:

\frac{dr}{d\theta}=0\\\\cos3\theta=0\\\\3\theta=\frac{\pi}{2}\\\\\theta=\frac{\pi}{6}

However, the values of 5π/6 and 9π/6 are also available, because makes the sinusoidal function equal  to 1.

hence, the answer is:

\theta_1=\frac{\pi}{6} \\\\\theta_2=\frac{5\pi}{6}\\\\\theta_3=\frac{9\pi}{6}=\frac{3\pi}{2}

answer b

7 0
3 years ago
The number of bacteria in a refrigerated food product is given by N ( T ) = 27 T 2 − 180 T + 100 N(T)=27T2-180T+100, 7 < T &l
NeX [460]

Answer:

N(T(t))=432t^2-374.4t-118.88

The number of Bactria after 5.8 hours is 12242.

Step-by-step explanation:

The number of bacteria in a refrigerated food product is given by

N(T)=27T^2-180T+100

where, T is the temperature of the food.

When the food is removed from the refrigerator, then the temperature is given by

T(t)=4t+1.6

We need to find the composite function N(T(t)).

N(T(t))=N(4t+1.6)

N(T(t))=27(4t+1.6)^2-180(4t+1.6)+100

N(T(t))=432t^2+345.6t+69.12-720t-288+100

N(T(t))=432t^2-374.4t-118.88

where N(T(t)) is the number of bacteria after t hours.

Substitute t=5.8 in the above function.

N(T(5.8))=432(5.8)^2-374.4(5.8)-118.88

N(T(5.8))=14532.48-2290.4

N(T(5.8))=12242.08

N(T(5.8))\approx 12242

Therefore, the number of Bactria after 5.8 hours is 12242.

7 0
3 years ago
Can you help me in this question
Andre45 [30]

9514 1404 393

Answer:

  the correct choice is marked

Step-by-step explanation:

The elements are 1, 4, {4}, {9}. That is, any subset that includes 1 must include it without braces. Any subset that includes 9 must include it with braces.

  {4, {9}, 1} is a subset of A

6 0
3 years ago
Lin runs 12 laps around a track in 15 minutes.
nalin [4]

Answer:

1.25

Step-by-step explanation:

15/12

5 0
3 years ago
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