With what?
because u didnot add any numbers 2 the question though
Let x be the shorter leg, then the longer is 6x+22 and the hypotenuse is 6x+23.
x² + (6x+22)² = (6x+23)²
x² + 36x² + 264x + 484 = 36x² + 276x + 529
x² - 12x - 45 = 0
(x+3)(x-15)=0
x=-3 or 15. since you can't have negative length discard-3, then the sides are 15, 112, and 113
Answer:
3,968,253.968253968
Step-by-step explanation:
The area of a sector is given by
.. A = (1/2)r^2*θ . . . . . θ is the central angle in radians
The area of an isosceles triangle with legs length r is
.. A = (1/2)r^2*sin(θ) . . . θ is the angle between same-length legs
The shaded area is the difference between these
.. A = (1/2)r^2*(θ -sin(θ))
.. = (1/2)*(18.6 m)^2*(π*123/180 -sin(123°))
.. ≈ 226.3 m^2
Your answer is any numbers that complete the equation.
<h2><u><em>
(6,2)</em></u></h2><h2><u><em>
(2,4)</em></u></h2><h2><u><em>
(8,1)</em></u></h2>
The first number would be the x, the second number would by y
If you plug those numbers in, the fulfill the equation.
There is an infinite number of solutions to this problem
