Answer:
A)n= 703.96
B)n= 602.308
Step by step Explanation:
Given that you want to be 99% confident that the sample percentage is within 3.1 percentage points of the true population percentage.
Then z/2 = 1.645
And M = 3.1% = 0.031
A)Nothing is known therefore,
p = q = 0.50
E=0.031
For 90% confidence, z = 1.645
n = (zα/₂)²(p)(1-p)/M²
n= 1.645²× 0.5 × 0.5/0.031²
n= 703.96
Therefore, 703.96randomly selected air passengers must be surveyed to be 99%
B)we know that recent surveys surgest that about 38% of all air passengers prefer an aisle seat, thus p = 35% = 0.35
n = (zα/₂)²(p)(1-p)/M²
n= (1.645²× 0.31 × 0.69)/0.031²
n= 602.308
Hence, 602.308 randomly selected air passengers must be surveyed to be 90% confident that the sample percentage is within 3.1 percentage points of the true population percentage.
4a. 99m + 81 = 130m. 4b. 40 + 30z = 70z
5a. 24v + 18 = 41v. 5b. 12c + 16 = 28c
6c. 44 + 48v= 92v. 6b. 40 + 12s = 52s.
First we can simplify f(x) to make it a little easier. We can write it as
4x^3+2x^2-7x+4 by combining like terms
The we just subtract g(x) from f(x) and simplify
4x^3+2x^2-7x+4-(5x^3-7x+4) and remember to distribute the negative to g(x)
4x^3+2x^2-7x+4-5x^3+7x-4 (combine like terms)
-x^3+2x^2
In factored form, this becomes
-x^2(x-2)
Hope this helps
Selling price of app per user = $10 per month
Total no. of user in first month = 10
To tal no. of user added per month = 7
We have to find how much money is earned in one year
So the formula is n/2 * (2a +(n-1)d)
Here we have n = 12 which is total no. of months
a = 100 , which is money earned in one month
d = 70 , which is increase in money earned per month
So money earned in a year comes out to be 5820
X could either be 4 or 5, depending on which x the question asks. If you have to chose one answer go with 5 because it's associated with the y.
