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Levart [38]
3 years ago
14

Fred and Ted are interested in the average height of NC State students. They randomly sample students from NC State and construc

t confidence intervals from their data. Fred sampled 121 students to construct his confidence interval. Ted sampled 144 students to construct his confidence interval; both create histograms for their data which have symmetric, unimodal, and roughly bell-shaped distributions. Which of the following is true about the margins of error for these experiments?
a. Fred's margin of error is larger than Ted's.
b. Ted's margin of error is larger than Fred's.
c. Fred and Ted have the same size margins of error.
d. We are unable to determine which margin of error is larger without knowing more about Fred and Ted's samples.
Mathematics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

a. Fred's margin of error is larger than Ted's.

Step-by-step explanation:

Margin of error of a confidence interval:

M = z\frac{\sigma}{\sqrt{n}}

In which z is related to the confidence level(the higher the confidence level the larger the value of z) \sigma is the standard deviation of the population and n is the size of the sample.

From this, we have that:

A higher confidence level leads to a larger margin of error.

A larger sample size leads to a smaller margin of error.

In this question:

Same confidence level.

Fred's sample is smaller, so his margin of error will be larger.

The correct answer is given by option a.

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ASAP PLZZZ Find the area of the shaded polygons:
lora16 [44]

Step-by-step explanation:

You can use the Pick's theorem:

A=i+\dfrac{b}{2}-1

where

<em>i</em><em> - number of lattice points in the interior located in the polygon</em>

<em>b</em><em> - number of lattice points on the boundary placed on the polygon's perimeter</em>

<em />

1.\\i= 5;\ b=12\\\\A=5+\dfrac{12}{2}-1=5+6-1=10\\\\2.\\i=3;\ b=4\\\\A=3+\dfrac{4}{2}-1=3+2-1=4\\\\3.\\i=5;\ b=10\\\\A=5+\dfrac{10}{2}-1=5+5-1=9

5 0
3 years ago
Read 2 more answers
A farmer finds that if she plants 50 trees per acre, each tree will yield 80 bushels of fruit. She estimates that for each addit
pashok25 [27]

Answer:

28

Step-by-step explanation:

From the given information:

Let x be the number of trees.

F(x) = (50 +x) (20 - 3x)

F(x) = 1000 - 150x + 20x - 3x²)

F(x) = -3x² - 130x + 1000

Differentiating F(x) with respect to x;

F'(x) = \dfrac{d}{dx}( -3x^2- 130x + 1000)

F'(x) = ( -3(2x)- 130(1) +0)

F'(x) = -6x -130

Now; we set F'(x) to be equal to zero to determine the critical value;

-6x - 130 = 0

x = - 130/6

Differentiating F''(x) with respect to x

F''(x) = \dfrac{d}{dx}( -6x- 130)

F''(x) = ( -6(1))

F''(x) = -6 (<0)

Thus; by the second derivative, the revenue function F(x) is maximum when x = -130/6

Therefore, the number of trees she should plant per acre to maximize her harvest is:

50 + x = 50 - 130/6

= 85/3

\simeq 28

Therefore, the number of trees per acre to maximize the harvest is 28

6 0
3 years ago
PLEASE HELP IF YOU DONT KNOW THE ANSWER PLEASE LEAVE
Alexxandr [17]

Answer:

the box is 6

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Use a system of equations to solve this problem.
Grace [21]
X = amount of seeds.

y = amount of dried fruits.

we know the snack mix contains both, and we know is 10oz, thus x + y = 10, whatever ounces "x" and "y" are.

how much is it for "x" ounces if each one costs $1.5?  well is just 1.5*x or 1.5x.

how much is it for "y" ounces if each one costs $2.5?  well is just 2.5*x or 2.5x.

the mix contains 10 ounces, each of which costs $2.2 each, how much will it be then for 10 oz?  well, is just 10 * 2.2, or $22.

since the whole 10 oz snack mix costs 22 bucks, then 1.5x + 2.5y = 22.

\bf \begin{cases}&#10;x+y=10\implies \boxed{y}=10-x\\&#10;1.5x+2.5y=22\\&#10;-------------\\&#10;1.5x+2.5\left( \boxed{10-x} \right)=22&#10;\end{cases}&#10;\\\\\\&#10;1.5x+25-2.5x=22\implies -x+25=22\implies 3=x

how many ounces of dried fruit is there anyway?  well, y = 10 - x.
4 0
3 years ago
1. How is being able to find the least common
Igoryamba

Step-by-step answer:

For relatively small denominators, the easiest way is to multiply the two denominators AND divide by the highest common factor (HCF).

For example, adding 5/24+3/16

24*16 = 384  

(use a calculator if necessary, for mental calculation, 24*16=20^2-4^2=400-16=384 ).

The highest common factor (HCF) is 8, since 24/8=3, 16/8=2, 3 and 2 do not have any more common factors, so it is the HCF.

The lowest common multiple (LCM) is then 384/8 = 48

For someone good at factoring, we see that the factors are:

24={2^3,3}

16={2^4} = {2^3,2}

so the LCM is either 16*3=48, or 24*2=48.

3 0
3 years ago
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