Question

If g(x)=x+1/x-2 and h(x)=4-x,what is the value of (g.h)(-3)?

Answer 1

Answer:

$g.h(-3) = \frac{14}{5}$

Step-by-step explanation:

We are given these following functions:

$g(x) = \frac{x + 1}{x - 2}$

$h(x) = 4 - x$

Multiplication function:

$g.h(x) = \frac{x + 1}{x - 2} \times (4 - x) = \frac{(x+1)(4-x)}{x - 2}$

At x = -3

$g.h(-3) = \frac{(-3+1)(4-(-3))}{-3 - 2} = \frac{(-2)(7)}{-5} = \frac{-14}{-5} = \frac{14}{5}$

So

$g.h(-3) = \frac{14}{5}$