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e-lub [12.9K]
3 years ago
5

If g(x)=x+1/x-2 and h(x)=4-x,what is the value of (g.h)(-3)?

Mathematics
1 answer:
dlinn [17]3 years ago
8 0

Answer:

g.h(-3) = \frac{14}{5}

Step-by-step explanation:

We are given these following functions:

g(x) = \frac{x + 1}{x - 2}

h(x) = 4 - x

Multiplication function:

g.h(x) = \frac{x + 1}{x - 2} \times (4 - x) = \frac{(x+1)(4-x)}{x - 2}

At x = -3

g.h(-3) = \frac{(-3+1)(4-(-3))}{-3 - 2} = \frac{(-2)(7)}{-5} = \frac{-14}{-5} = \frac{14}{5}

So

g.h(-3) = \frac{14}{5}

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