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Mademuasel [1]
3 years ago
9

1. Cabrini goes out for dinner, and the price of her meal is $18. The sales tax on the meal is 6%, and she also wants to leave a

20% tip. What is the total price of the meal? PLEASE I WIL FAIL AND NOT GET A NEW ROOM!!!!
Mathematics
1 answer:
Daniel [21]3 years ago
7 0

Answer:

19.64

Step-by-step explanation:

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djyliett [7]

Answer:

The radius is 1

Step-by-step explanation:

7 0
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3(x + y + h)=<br> Can someone help me with this
Nastasia [14]

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3x +3y +3h

that’s the farthest you can solve since you don’t know the variable’s values

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2 years ago
SOMEONE HELP ME PLEASE!<br> ¡ALGUIEN QUE ME AYUDE POR FAVOR!
marshall27 [118]
1 = 11
2 = 79
3 = 3
4 = -4
5 = 0
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2 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words.
lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17   eq(1)

y = -1/2x            eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 5/4, b =0 and c = -17

x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}

Finding value of y:

y = -1/2x

y=-1/2(\frac{\pm2\sqrt{85}}{5})

y=\frac{\pm\sqrt{85}}{5}

System A has 4 real solutions.

System B

y = x^2 -7x + 10    eq(1)

y = -6x + 5            eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-1 and c =5

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9    eq(1)

8x - y = -17        eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17    

8(-2) - y = -17    

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

4 0
3 years ago
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A 98% confidence interval is found to be (50, 60). What is the margin of error?
miss Akunina [59]

Answer:

D. 5

Step-by-step explanation:

Mean: (50+60)/2

110/2

55

Margin of error:

60 - 55

5

3 0
3 years ago
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