Answer:
1.125
Step-by-step explanation:
729/512=1.423828125
3√1.423828125=1.125
Answer:
x=24
Step-by-step explanation:
x/2+3=15
-3 both sides
x/2=15−3
15-3=12
x/2=12
12*2=24
x=24
<span>If set X is made up of the possible ways five students, represented by A, B, C, D, and E, can be formed into groups of three, then the set X consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, CDE} (note that triple ABC is the same as triple ACB, or BCA, or BAC, or CAB, or CBA). The set X totally contains 10 elements (triples). The first statement is true.
</span>
<span>If set
Y is made up of the possible ways five students can be formed into
groups of three if student A must be in all possible groups, then </span><span>the set Y consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE} and contains 6 elements. The second statement is also true.
</span>
<span>If person E must be in each group, then there can be only one group is false statement, because you can see from the set X that triples which contains E are 6.
</span>
<span>There are three ways to form a group if persons A and C must be in it. This statement is true and these groups are ABC, ACD, ACE.</span>
Answer:
<h3>C. <em>No, he did not calculate the distance correctly.</em></h3>
Step-by-step explanation:
The question is incomplete. Here is the complete question.
<em>A circle centered at (–1, 2) has a diameter of 10 units. Amit wants to determine whether (2, –2) is also on the circle. His work is shown below. The radius is 5 units. Find the distance from the center to (2, –2). The point (2, –2) doesn’t lie on the circle because the calculated distance should be the same as the radius. Is Amit’s work correct? No, he should have used the origin as the center of the circle. No, the radius is 10 units, not 5 units. No, he did not calculate the distance correctly. Yes, the distance from the center to (2, –2) is not the same as the radius</em><em>.</em>
<em />
<em>For Amit to determine whether the point (2, -2) is on the circle, we will need to find the distance between the coordinates (–1, 2) and (2, -2) using the formula:</em>
<em>D = √(y₂-y₁)² + (x₂-x₁)² </em>
<em>D = √(-2-2)² + (2-(-1))² </em>
<em>D = √(-4)² + (2+1)²</em>
<em>D = √16 + 9</em>
<em>D = √25</em>
<em>D = 5 units</em>
<em />
<em>Since the distance between the coordinate is equal to the radius of the circle, hence the coordinate (2, -2) lies on the circle.</em>
<em />
<em>Hence Amit is wrong because he did not calculate the distance correctly</em>