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andreev551 [17]
3 years ago
9

Three different numbers need to be placed in order from least to greatest. For example, if the numbers are ordered 9, 16, 4, the

y should be reordered as 4, 9, 16. Which of the following algorithms can be used to place any three numbers in the correct order?
If the first number is greater than the last number, swap them. Then, if the first number is greater than the middle number, swap them.

If the first number is greater than the last number, swap them. Then, if the first number is greater than the middle number, swap them.
A

If the first number is greater than the middle number, swap them. Then, if the middle number is greater than the last number, swap them.

If the first number is greater than the middle number, swap them. Then, if the middle number is greater than the last number, swap them.
B

If the first number is greater than the middle number, swap them. Then, if the middle number is greater than the last number, swap them. Then, if the first number is greater than the last number, swap them.

If the first number is greater than the middle number, swap them. Then, if the middle number is greater than the last number, swap them. Then, if the first number is greater than the last number, swap them.
C

If the first number is greater than the middle number, swap them. Then, if the middle number is greater than the last number, swap them. Then, if the first number is greater than the middle number, swap them.
Computers and Technology
1 answer:
Anna11 [10]3 years ago
3 0

Answer:A

Explanation:

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6 0
2 years ago
Write a program that takes user input describing a playing card in the following short-hand notation:
siniylev [52]

Answer:

In python Language:

cardNotation = raw_input("Enter card notation: ")

 

# Create a dict for values

 

cardColors = {"D": "Diamonds",

             "H": "Hearts",

             "S": "Spades",

             "C": "Clubs"}

 

cardNumberValues = {"A": "Ace",

                   "J": "Jack",

                   "Q": "Queen",

                   "K": "King",

                   "2": "Two",

                   "3": "Three",

                   "4": "Four",

                   "5": "Five",

                   "6": "Six",

                   "7": "Seven",

                   "8": "Eight",

                   "9": "Nine",

                   "10": "Ten"}

 

# Handle cases when 10 comes in input

if len(cardNotation) == 3:

 

   number = cardNotation[:2]

   color = cardNotation[2:]

   print cardNumberValues.get(number) + " of " + cardColors.get(color)

 

elif len(cardNotation) == 2:

 

   number = cardNotation[:1]

   color = cardNotation[1:]

   print cardNumberValues.get(number) + " of " + cardColors.get(color)

 

else:

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6 0
3 years ago
Assume the system with 256B memory and 64B cache and the block size of 16 bytes. I.e., there are 4 blocks in the cache. (a) For
Nataliya [291]

Answer:

Check the explanation

Explanation:

1.

System = 256Byte = 8 bit

Cache = 64B , block size = 16 byte.

A) Direct Mapped Cache:

Block offset = log (Block size) = log 16 = 4bit

Total # of block inside cache = 4.

Therefore index offset = log 4 = 2bit.

Remaining is tag bits.

Therefore tag bits = 8-(4+2) = 8-6 = 2 bits

Tag                              Index offset                                Block offset

(2 bits)                             (2 bits)                                           (4 bits)

Fully associative cache :

In fully associative cache, any of main memory block can be placed anywhere in cache. Therefore index offset =0 bits.

Therefore tag bits = 8-block offset bit= 8-4 =4bits

Tag                               Block offset

(4 bits)                                (4 bits)

4 0
3 years ago
How do you change the username on here?
never [62]

Answer:

I don't think you can. You can try to make an email that has the name you want and use that.

Explanation:

6 0
3 years ago
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Sauron [17]

Solution:

Since no language was specified, this will be written in Python.

n1, n2, n3 = input ("Enter three names: ").split()

print(n3)

print(n2)

print(n1)

Cheers.

4 0
3 years ago
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