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2 years ago

I need help ASAP!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Rudik [331]2 years ago

8 0

The answer is 56/33

kiruha [24]2 years ago

3 0

Answer: 56/33

Step-by-step explanation: Tan= Opposite over Adjacent or O/A

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One-fourth of r subtracted from ten is greater than five

rosijanka [135]

Im not 100% about how this question is explained or written but i think its 8

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3 years ago

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valentinak56 [21]

Answer:

Step-by-step explanation:

Slope- intercept form

y= mx +c, where m is the slope and c is the y-intercept.

The given equation is in the slope-intercept form and hence we can easily identify its slope by looking at the coefficient of x.

y= 2x +7

slope= 2

Parallel lines have the same slope, thus the slope of the parallel line is also 2.

Substitute m= 2 into the general equation:

y= 2x +c

Substitute a pair of coordinates into the equation to find the value of c:

When x= 3, y= 11,

11= 2(3) +c

11= 6 +c

c= 11 -6

c= 5

Therefore the equation of the line is y= 2x +5.

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2 years ago

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A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$