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storchak [24]
2 years ago
11

I need help ASAP!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Rudik [331]2 years ago
8 0
The answer is 56/33
kiruha [24]2 years ago
3 0

Answer: 56/33

Step-by-step explanation: Tan= Opposite over Adjacent or O/A

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PPPLLLLEEEAASSSEEEE HHHEEEELLLLPPPPP!!!!!!!
Yuliya22 [10]

Answer:

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Step-by-step explanation:

Because the center of dilation is at (0, 0), or the origin, we can just multiply the x and y values of each point by the scale factor of 13.

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Read more on Brainly.com - brainly.com/question/11445104#readmore

4 0
3 years ago
Tell whether the given number is a solution of each question. ( Must show work for credit)
guajiro [1.7K]

Answer/Step-by-step explanation:

1. 9 = 2a + 3 ; 3

Let's solve for a.

9 - 3 = 2a (subtraction property of equality)

6 = 2a

\frac{6}{2} = a (division property of equality)

3 = a

a = 3

Therefore, 3 is a solution to 9 = 2a + 3

2. 5n - (-30) = 5 ; 7

5n + 30 = 5 (- × - = +)

5n = 5 - 30 (Subtraction property of equality)

5n = -25

\frac{5n}{5} = \frac{-25}{5} (division property of equality)

n = -5

Therefore, 7 is not a solution of 5n - (-30) = 5

3. 4.4r - 2.8 = 1.6 ; 1

4.4r = 1.6 + 2.8

4.4r = 4.4

\frac{4.4r}{4.4} = \frac{4.4}{4.4}

r = 1

Therefore, 1 is a solution of 4.4r - 2.8 = 1.6.

5 0
2 years ago
On $500 at 6% for 18 months what is the interest
blsea [12.9K]
It would be $45. The equation is 500×0. 06×1.5
6 0
3 years ago
Necesito las respuestas
Stels [109]

Answer:

I need it in English please so I can helps

3 0
1 year ago
Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand
Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

And a standard deviation of 3.6.  

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0
3 years ago
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