1. 2 ft 9 in
2. 1 ft 1 in
3. 8 ft 7 in
4. 6 ft 5 in
5. 8 ft. 1 in
6. 4 ft 4 in
7. 10 ft 2 in
Answer:
The correct answer is - $720 or 20%.
Step-by-step explanation:
Given:
Total expense = 3600
Electric=30%
Heating and gas=50%
Water and sewer=X%
Solution:
For electric: 3600*30/100 = 1080
for heating and gas: 3600*50/100 = 1800
Left money for expense of water and shower = total - (electric and heating)
= 3600-1880
= 720
Percentage of water and shower = 720*100/3600
= 20%
Answer:
Step-by-step explanation:
To find out how many gram the puppy increase each day,here's what we can do:
weight of day 4 - weight of day 2
=365 - 305
=60g
To comfirm,we can use another pair
weight of day 4 - weight of day 2
=485-425
=60g
From the above,we can see that the puppy increase 60 grams each two days,meaning that it would increase 60÷2=30 gram each day.
We can then find its weight of age of 5 days:
365+30
=395g
Thus the answer is D.395
Hope it helps!
Answer:
See verification below
Step-by-step explanation:
We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that
![1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}](https://tex.z-dn.net/?f=1-P%3D1-%5Cfrac%7Bce%5Et%7D%7B1%2Bce%5Et%7D%3D%5Cfrac%7B1%2Bce%5Et-ce%5Et%7D%7B1%2Bce%5Et%7D%3D%5Cfrac%7B1%7D%7B1%2Bce%5Et%7D)
Now, differentiate to obtain
![\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}](https://tex.z-dn.net/?f=%5Cfrac%7BdP%7D%7Bdt%7D%3D%28%5Cfrac%7Bce%5Et%7D%7B1%2Bce%5Et%7D%29%27%3D%5Cfrac%7B%28ce%5Et%29%27%281%2Bce%5Et%29-%28ce%5Et%29%281%2Bce%5Et%29%27%7D%7B%281%2Bce%5Et%29%5E2%7D)
![=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%28ce%5Et%29%281%2Bce%5Et%29-%28ce%5Et%29%28ce%5Et%29%7D%7B%281%2Bce%5Et%29%5E2%7D%3D%5Cfrac%7Bce%5Et%2Bce%5E%7B2t%7D-ce%5E%7B2t%7D%7D%7B%281%2Bce%5Et%29%5E2%7D%3D%5Cfrac%7Bce%5Et%7D%7B%281%2Bce%5Et%29%5E2%7D)
To obtain the required form, extract a factor in both the numerator and denominator:
![\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)](https://tex.z-dn.net/?f=%5Cfrac%7BdP%7D%7Bdt%7D%3D%5Cfrac%7Bce%5Et%7D%7B1%2Bce%5Et%7D%5Cfrac%7B1%7D%7B1%2Bce%5Et%7D%3DP%281-P%29)