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3 years ago

He speeds (in MPH) of automobiles traveling in a city are given below:

Mathematics

1 answer:

professor190 [17]3 years ago

7 0

Answer:

Mean speed = 41.3 mph

Step-by-step explanation:

Given that,

The speeds of an automobiles are given below:

20, 35, 42, 52, 65, 49, 24, 37, 23, 41, 50, 58

We need to find the mean speed of the cars.

Mean = sum of observations/ no. of observation

$M=\dfrac{20+35+42+52+65+49+24+37+23+41+50+58}{12}\\\\M=41.3$

So, the mean speed of the cars is equal to 41.3 mph.

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Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

Find the value of y

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

Find the values of x

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

Someone help me 19-25

DerKrebs [107]

19-25=-6 that is your answer

4 0

3 years ago

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Please help me on this question

viva [34]

I am stuck on same thing as u

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

2. - 2x + xy + 5x – 4xy + x

andrezito [222]

-3xy+4x is the answer

7 0

3 years ago

The width of a rectangle is 5 more than twice the length. If the perimeter of the rectangle is 190 meters ,what is the width of

slega [8]

P=2(l+w)

190=2[(2l+5)+l)
190=4l+10+2l
190=6l+10
180=6l
l=30

190=2(30+w)
190=60+2w
130=2w
w=65

The width of the rectangle is 65.

6 0

3 years ago