Answer:
S: $0.18
T: $11.73
Step-by-step explanation:
T=tickets
S=snacks
2t+3s=24
5s=28
Divide 5 with 28.
Roughly $0.18
s=0.18.
2t+3(0.18)=24
2t+0.54=24
Subtract 0.54:
2t+0.54-0.54=24-0.54
2t=23.46
Divide 2:
t=11.73
So A snack is $0.18, and a ticket is $11.73
Hope this helped!
The best way to find your answer is to divide 193 by 400 to get .4825 and to make sure if it is the answer you take 400 and multiply .4825 and it will be 193 so .4825 = 48.25%
Sorry I can’t buddy........................................................:(
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
P(brown) = 12% = 0.12
P(Yellow) = 15% = 0.15
P(Red) = 12% = 0.12
P(blue) = 23% = 0.23
P(orange) = 23% = 0.23
P(green) = 15% = 0.15
A.) Compute the probability that a randomly selected peanut M&M is not yellow.
P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85
B.) Compute the probability that a randomly selected peanut M&M is brown or red.
P(Brown) or P(Red) :
0.12 + 0.12 = 0.24
C.) Compute the probability that three randomly selected peanut M&M’s are all brown.
P(brown) * P(brown) * P(brown)
0.12 * 0.12 * 0.12 =0.001728
D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.
P(3 blue)' = 1 - P(3 blue)
P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167
1 - P(3 blue) = 1 - 0.012167 = 0.987833
If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.
P(1 blue) + p(2 blue) + p(3 blue)
(0.23) + (0.23*0.23) + (0.23*0.23*0.23)
0.23 + 0.0529 + 0.012167
= 0.295067
Answer:
16.17684994
Step-by-step explanation:
First diagonal
x^2 = a^2 + b^2
x^2 = 5^2 + 6^2
x^2 = 61
x ≈ 7.810249676
Second diagonal
x^2 = a^2 + b^2
x^2 = 7.810249676^2 + 3^2
x^2 = 70
x ≈ 8.366600265
Sum of both diagonals
8.366600265 + 7.810249676
= 16.17684994
