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3 years ago

Plz help me!!!! I have 2 questions for 20 points, be serious about this!

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

8 0

Answer:

b d

Step-by-step explanation:

add then subtract the fractions

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The graph shows the relationship between sugar and water in a fruit punch recipe.

Zinaida [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Question 2 of 25

notsponge [240]

The inverse function of f(x) = 6x + 4 is f^-1(x) = (x - 4)/6

<h3>How to determine the inverse function?</h3>

The function is given as:

f(x) = 6x + 4

Rewrite as:

y = 6x + 4

Swap x and y

x = 6y + 4

Subtract 4 from both sides

6y = x - 4

Divide through by 6

y = (x - 4)/6

Rewrite as:

f^-1(x) = (x - 4)/6

Hence, the inverse function of f(x) = 6x + 4 is f^-1(x) = (x - 4)/6

Read more about inverse functions at:

brainly.com/question/2541698

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6 0

2 years ago

Tiles. Show your work<br>5. X+4= 4

omeli [17]

Here’s the answer!!!!!!

3 0

3 years ago

Ashley, Frank, and Chang sent a total of 73 text messages over their cell phones during the weekend. Frank sent 7 more messages

jenyasd209 [6]

Answer:

Ashley=13 messages

Frank=20 messages

Chang=2x+14=40 messages

Step-by-step explanation:

Number of texts sent by each person;

Ashley=x

Frank=x+7

Chang=2(x+7)=2x+14

Total number of text messages=Number sent by Ashley+Number sent by Frank+Number sent by Chang

where;

Total number of text messages=73

Replacing;

73= x+(x+7)+(2x+14)

x+x+2x+7+14=73

4x+21=73

4x=73-21

4x=52

x=52/4

x=13

Ashley=13 messages

Frank=x+7=13+7=20 messages

Chang=2x+14=(2×13)+14=40 messages

6 0

3 years ago

A force of 50 pounds acts on an object at an angle of 45 degrees. A second force of 75 pounds acts on the object at an angle of

Contact [7]

Answer:

The magnitude of the resultant force is:

$R=100.3 \:pound$

The direction is:

$\theta=1.2^{\circ}$

Step-by-step explanation:

Let's find the components of each vector is x and y-directions first.

<u>Sum of x-component vector forces.</u>

$F_{tot-x}=F_{1}cos(45)+F_{2}cos(30)$

$F_{tot-x}=50cos(45)+75cos(30)$

$F_{tot-x}=100.3 \: pound$

<u>Sum of y-component vector forces.</u>

$F_{tot-y}=-F_{1}sin(45)+F_{2}sin(30)$

$F_{tot-y}=-50sin(45)+75sin(30)$

$F_{tot-y}=2.1 \: pound$

The magnitude of the resultant force is:

$R=\sqrt{100.3^{2}+2.1^{2}}$

$R=100.3 \:pound$

The direction is:

$tan(\theta)=\frac{2.1}{100.3}$

$\theta=arctan(\frac{2.1}{100.3})$

$\theta=1.2^{\circ}$

I hope it helps you!

4 0

3 years ago