Answer:
what's the question, what is it asking for??

- <em>c.</em><em>)</em><em> </em><em>x</em><em>=</em><em>2</em>
<h2><em>hope</em><em> it</em><em> helps</em><em>!</em></h2>
Answer:
72,90
Step-by-step explanation:
Since 9 is the biggest number so list multiples of 9 between 55- 101 range.
Which are 63, 72, 81, 90, 99. Any number that is a multiple of 9 is a multiple of 3 because 3x 3 = 9. 9 is a multiple of 3.
Any even number is a multiple of 2.
Only 72 and 90 are even numbers.
So 72 and 90 are numbers divisible by 2, 3, 9.
V1 + V2
V1 = 1*2*1 = 2
V2 = 5*2*2 = 20
V1 + V2
2+20
22
Q.34

The infinite geometric series is converges if |r| < 1.
We have r =1.002 > 1, therefore our infinite geometric series is Diverges
Answer: c. Diverges, sum not exist.
Q.35

The infinite geometric series is converges if |r| < 1.
We have r = 4/5 < 1, therefore our infinite geometric series is converges.
The sum S of an infinite geometric series with |r| < 1 is given by the formula :

We have:

substitute:

Answer: c. Converges, -25.