Question

Please help me with this question.

Answer 1

Answer: C. $\frac{x-3}{3x+1}$

Step-by-step explanation:

$\frac{x+2}{x^2+5x+6}$ ÷ $\frac{3x+1}{x^2-9}$ =

$\frac{x+2}{x^2+5x+6} * \frac{x^2-9}{3x+1} = \frac{x+2}{(x+3)(x+2)} * \frac{(x-3)(x+3)}{3x+1} =$

multiply and cancel out same terms / simplify

first x+3 and x+3 cancel out

then x+2/x+2 cancels out to make 1

$\frac{x+2}{(x+2)} * \frac{(x-3)}{3x+1} = \frac{x-3}{3x+1}$