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LuckyWell [14K]

3 years ago

15

Is 36 a factor. yes or no

2 answers:

Leona [35]3 years ago

7 0

Yes because 6x6 is 36

kondaur [170]3 years ago

3 0

There is no such thing as 36 being a factor but it has factors and its a factor of 72

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Charra [1.4K]

Answer:

Step-by-step explanation:

5 0

2 years ago

A baseball player throws a 95mph fastball straight up into the air. The position equation, which gives the height of the ball at

Lana71 [14]

Set s(t) = 0 which means it hits the ground. The formula doesn't fit the parameters given as it shows that the pitcher is standing on something 37 feet high.
<span>s(t)=-16t^2+140t+37 and has an initial velocity of 140.
Graphing or solving this, t= 9 seconds when it hits the ground.
The velocity V(t) is the derivative of s(t)
V(t) = -32t+140
V(9) = -148 ft/second which is going down
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3 0

2 years ago

I need help finding what the answers are in the empty spaces? Anyone willing to help me find them or tell me?

Readme [11.4K]

Answer:

1) He earns $288 a week

2) 270.20

3) 226.97

4) 215. 62

6) 967.68

Step-by-step explanation:

4 0

2 years ago

a customers total bill is $50.50. The company charges a monthly fee of $28 plus 5 cents for each call. Use n to represent the nu

Doss [256]

.05n + $28 = $50.50

(.05n = $22.50)100

5n = 2250

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7 0

3 years ago

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

$\$180.55$

Step-by-step explanation:

step 1

<u><em>Simple interest</em></u>

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

<u><em>Interest compounded annually</em></u>

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

$A=2,250(1.04)^{10}$

$A=\$3,330.55$

step 3

Find the differences between the two final amounts

$A=\$3,330.55-\$3,150=\$180.55$

5 0

3 years ago