Answer:
Option 3. y = csc ∅ is the right answer.
Step-by-step explanation:
In a function y = cosec ∅ we put the value of ∅ at 0,π/4,π/2,π,3π/2.
y = cosec 0 = ∞ Therefore function is not defined at ∅ = 0
y = cosec π/4 = √2 = 1.41
y = cosec π/2 = 1
y = cosec π = ∞ not defined
y = cosec 3π/2 = -1
y = cosec 2π = ∞ again not defined
While analyzing the value of expression we can say that the graph is of y = cosec ∅.
Similarly if we analyze other expressions for the values of ∅ then the graph will not match.
We have the following statements and results.
A. A rhombus is a quadrilateral.
True. A rhombus is a quadrilateral all of which sides have the same length.
B. A quadrilateral is a polygon with four angles.
True. A polygon is a plane figure with at least three straight sides and angles, and typically five or more.
C. In quadrilateral PQRS, ∠P and ∠S are opposite angles.
False. If we have a quadrilateral PQRS, that means that ∠P and ∠S are consecutive angles, not opposite.
D. The diagonals of a rhombus are perpendicular and bisect each other.
True. It is true that the diagonals of a rhombus are always perpendicular and bisect each other.
Answer.
Statement C is false.
Answer:
graph y=12x-10-3 has a larger slope and does not pass through the origin, however, y=1x has a smaller slope and passes through the origin
Step-by-step explanation:
If you graph these lines it will help you to visually see this also. My graph is not exact but I hope it is helpful!