Answer:
The values of x and y are x = 6 and y = 9Step-by-step explanation:
MNOP is a parallelogram its diagonal MO and PN intersected at point A
In any parallelogram diagonals:
Bisect each other
Meet each other at their mid-point
In parallelogram MNOP
∵ MO and NP are its diagonal
∵ MO intersect NP at point A
- Point A is the mid-point pf them
∴ MO and NP bisect each other
∴ MA = AO
∴ PA = AN
∵ MA = x + 5
∵ AO = y + 2
- Equate them
∴ x + 5 = y + 2 ⇒ (1)
∵ PA = 3x
∵ AN = 2y
- Equate them
∴ 2y = 3x
- Divide both sides by 2
∴ y = 1.5x ⇒ (2)
Now we have a system of equations to solve it
Substitute y in equation (1) by equation (2)
∴ x + 5 = 1.5x + 2
- Subtract 1.5x from both sides
∴ - 0.5x + 5 = 2
- Subtract 5 from both sides
∴ - 0.5x = -3
- Divide both sides by - 0.5
∴ x = 6
- Substitute the value of x in equation (2) to find y
∵ y = 1.5(6)
∴ y = 9
The values of x and y are x = 6 and y = 9
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<em>x=</em><em> </em><em>0</em><em>.</em><em>6</em><em>°</em>
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Answer:
Step-by-step explanation:
<u>Given the circle:</u>
or
According to the equation, any point with one of the coordinate > 5 lies outside of the circle since the radius is 5 units.
The points 2, 3 and 4 have at least one of the coordinates greater than 5.
<u>Let's verify the point 1:</u>
Answer:
135 is correct answer of this question
Answer:
A) 150 m
B) 180.28 m
Step-by-step explanation:
A) In order to find the horizontal distance from the base of the cliff to the speed boat, use the Pythagorean theorem to calculate the length of the missing side.
We are told that one of the sides is 80 m and the hypotenuse is 170 m. Therefore,
- a² + b² = c²
- (80)² + b² = (170)²
- b² = 170² - 80²
- b² = 22500
- b = 150
The horizontal distance between the base of the cliff and the boat is 150 m.
B) Now, the side that was 80 m is now 100 m (includes the height that the helicopter is above Jumbo). The horizontal distance remains the same, 150 m, but the hypotenuse is different. Solving for the hypotenuse will give us the distance between the helicopter and the speed boat.
- (100)² + (150)² = c²
- 32500 = c²
- 180.28 = c
The distance between the helicopter and the speed boat is 180.28 m.
