Answer:
He has 3 quarters , 6 dimes and 16 nickles
Step-by-step explanation:
∵ Dimes is d , Quarter is q , nickels is n and pennies is p
∵ Quarter = 25 cents
∵ Dime = 10 cents
∵ Nickle = 5 cents
∵ Penny = 1 cent
∵ The remaining 35 coins are pennies ⇒ 35 cents
∵ He has $2.50 = 2.50 × 100 = 250 cents
∴ The value of quarters , dimes and nickels = 250 - 35 = 215 cents
∴ 25q + 10d + 5n = 215 ⇒ (1)
∵ d = 2q
∴ q = 1/2d ⇒ (2)
∵ n = 10 + d ⇒ (3)
Substitute (2) and (3) in (1)
∴ 25(1/2 d) + 10d + 5(10 + d) = 215
∴ 12.5d + 10d + 50 + 5d = 215
∴ 27.5d = 215 - 50
∴ 27.5d = 165
∴ d = 165 ÷ 27.5
∴ d = 6
∴ q = 1/2 (6) = 3
∴ n = 10 + 6 = 16
∴ He has 3 quarters , 6 dimes and 16 nickles
Use the Pythagorean theorem /look at the picture/
? = x
Replace x in the equation with 1 and solve.
F(x) = 2x
X = 1
F(1) = 2(1) = 2
The answer is 2
SA = 2πr² + 2πrh
• Factorize right side
SA = 2πr(r² + h)
• Divide both sides by 2πr
SA/2πr = r² + h
• Move r² to left side
h = r² - (SA/2πr)
