Use the formula y2-y1/x2-x1 and sub in points.
Answer:
Quadrilateral Area =24 estrat(each square value is 1) (6x8)/2
Step-by-step explanation:
Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Answer:
x=4
Step-by-step explanation:
2/3 x + 5/6 = x - 1/2
Multiply each side by 6 to clear the fractions
6(2/3 x + 5/6) = 6(x - 1/2)
Distribute
4x +5 = 6x-3
Subtract 4x from each side
4x+5 -4x = 6x-3-4x
5 = 2x-3
Add 3 to each side
5+3= 2x-3+3
8 =2x
Divide by 2
8/2 =2x/2
4 =x