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Answer:
B Barney stops less than a foot from the car.
Step-by-step explanation:
From the information given:
The initial speed of barney = 25 mph
Coefficient of friction = 0.7
Recall that
1 mph = 0.447 m/s
Then
= 25 × 0.447 m/s
= 11.175 m/s
The force of friction acting on the barney is expressed as:
a = 0.7 × 9.8 m/s
a = 6.86 m/s²
Since the force acts in an opposite direction to the motion of Barney, Thus the acceleration must also be negative.
a = -6.86 m/s²
Now;
Suppose Barney stops after traveling a distance (s), so that the final speed is zero.
Then;
Using the kinematic equation;
s = 9.09 m
Recall that;
1 m = 3.28 ft
So;
s = 9.09 m = 9.09 × 3.28 ft
s = 29.81 ft
∴
The distance traveled by the Barney is 29.81 ft which implies that Barney stops less than a foot from the car.