Answer:
<h3>80 feet</h3>
Step-by-step explanation:
Given the path of a projectile launched from a 16-ft-tall tower modeled by the equation y = −16t^2 + 64t +16
h is the maximum height reached
t is in seconds
The velocity of the projectile at its maximum height is zero;
velocity v = dy/dt
v = -32t + 64
Since v = 0 at maximum height
0 = -32t + 64
32t = 64
t = 2secs
Substitute t = 2secs into the equation of the height to get the maximum height.
y = −16t^2 + 64t +16
at t = 2secs
y = −16(2)^2 + 64(2) +16
y = -64 + 128 + 16
y = 64+16
y = 80 feet
Hence the maximum height, in feet, reached by the projectile is 80 feet
3a x 3a x 3a x 3a x 3a
= 243a
Area = Length x Width
Since the pool is a square, you will do 243a x 243a
Area = 59,049
Answer on the second photo with the numbers 3,4 and 5:
6 square
Step-by-step explanation:
3 times 4 : 2 =
12 : 2 =
12 : 2 = 6 square
Answer: the picture is not correct with the answer
Step-by-step explanation:
Answer:
-4,1
Step-by-step explanation:
I hope the attached image helps
