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3 years ago

What is the value of the sum 1/3 + 2/3+ 2/3+ 4/3 + 5/3+6/3+7/3+8/3

Mathematics

1 answer:

ollegr [7]3 years ago

6 0

<h3>What is the value of the sum 1/3 + 2/3+ 2/3+ 4/3 + 5/3+6/3+7/3+8/3</h3>

<h2>ANSWER</h2>

$\frac{35}{3}$

Decimal Form:

$11.6$

Mixed nunber Form:

$11 \frac{2}{3}$

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PLEASE HELP !! ILL GIVE BRAINLIEST !

fomenos

Answer:

20 + 0i

Step-by-step explanation:

(10 + 5i) + (10 - 5i) = 20 + 0i

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3 years ago

Rachel mows 5 lawns in 8 hours. At this rate how many lawns can she mow in 40 hour?

posledela

We can think of this as an equality

5 Lawns = 8 Hours

If she needs 40 hours, you can multiply 8 hours by 5 to get 40, but now it's not balanced. So, you need to multiply 5 to the other side too so:

5 x (5) = 8 x (5)

Therefore she mows 25 Lawns in 40 Hours

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3 years ago

F(x)=x^2+2x-1 <br>find f(-3)

emmasim [6.3K]

Answer:

Step-by-step explanation:

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3 years ago

bezimeni [28]

Answer:

260 stickers

Step-by-step explanation:

Let Gareth's stickers be x.

Hence Cheryl sticker is 160+x;

If Cheryl gave 185 stickers

to Gareth, it means:

Cheryl has at the moment;

160 + x - 185 = x - 25

At this time when Gareth receives 185 he now has:

x+ 185

Also when he receives x +185, he has 3 times Cherry's meaning:

x+185 =3(x-25)

x + 185 = 3x -75

185 + 75 = 3x-2x

260= x

x = 260.

Hence Gareth has 260 stickers

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3 years ago

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 450 gram setting. It

Arturiano [62]

Answer:

Test statistic = -2.25

P-value = 0.0199

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 450 gram

Sample mean, $\bar{x}$ = 441 grams

Sample size, n = 16

Alpha, α = 0.05

Sample variance = 256

$\sigma^2 = 256\\\sigma = \sqrt{256} = 16$

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 450\text{ grams}\\H_A: \mu < 450\text{ grams}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{441 - 450}{\frac{16}{\sqrt{16}} } = -2.25$

Now,

Degree of freedom =

$=n-1 = 16-1=15$

We can calculate the p-value from the table as:

P-value = 0.0199

Conclusion:

Since the p-value is smaller than the significance level we fail to accept the null hypothesis and reject it.

Thus, there is enough evidence to support the claim that the machine is under filling the bags .

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3 years ago