Answer:
-60
Step-by-step explanation:
The objective is to state whether or not the following limit exists
.
First, we simplify the expression in the numerator of the fraction.

Now, we obtain

and the fraction is transformed into

Therefore, the following limit is

You can plug in
in the equation, hence

Answer:
x = 1, y = -1
Step-by-step explanation:
If we have the two equations:
and
, we can look at which variable will be easiest to eliminate.
looks like it might be easy to get rid of, we just have to multiply
by 2 and y is gone (as -6y + 6y = 0).
So let's multiply the equation
by 2.

Now we can add these equations

------------------------

Dividing both sides by 5, we get
.
Now we can substitute x into an equation to find y.

Hope this helped!
Answer:
whats the question
Step-by-step explanation:
Answer:
Their slopes and y-intercepts are the same
Step-by-step explanation:
For example:
y=3x+5
y=3x+5
3x+5=3x+5
3x=3x
x=x
Thus, there's infinitely many solutions
Answer:
P(X ≥ 1) = 0.50
Step-by-step explanation:
Given that:
The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.
Then; the probability of success = 7/34 = 0.20588
Using Binomial distribution to determine the probability; we have:

where;
x = 0,1,2,...n and 0 < β < 1
and x represents the number of successes.
However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:
P(X ≥ 1) = 1 - P(X< 1)
P(X ≥ 1) = 1 - P(X =0)
![P(X \ge 1) = 1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%20%7B%5E3C__0%7D%20%280.21%29%5E0%20%281-0.21%29%5E%7B3-0%7D%20%5Cbigg%5D)
![P(X \ge 1) = 1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%201%20%5Ctimes%201%20%280.79%29%5E%7B3%7D%20%5Cbigg%5D)
P(X ≥ 1) = 1 - 0.50
P(X ≥ 1) = 0.50