Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Answer:
look from the tan A angle , the opposite is 28 and adjacent is 45
You need the percentages to answer the question
Answer:
(5.216) mean = 61.71
(5.217) standard deviation = 8.88
(5.218) P(X>=60) = 0.9238
(5.129) L = 79, U = 69
(5.130) P(X> or = U) = 0.7058
Step-by-step explanation:
The table of the statistic is set up as shown in attachment.
(5.216) mean = summation of all X ÷ no of data.
mean = 432/7 = 61.71 birds
(5.217)Standard deviation = √ sum of the absolute value of difference of X from mean ÷ number of data
S = √ /X - mean/ ÷ 7
= √551.428/7
S = 8.88
(5.218) P (X> or = 60)
= P(Z> or =60 - 61.71/8.8 )
= P(Z>or= - 0.192)
= 1 - P(Z< or = 0.192)
= 1- 0.0762
= 0.9238
(5.219)the 15th percentile=15/100 × 7
15th percentile = 1.05
The value is the number in the first position and that is 79,
L= 79
85th percentile = 85/100 × 7 = 5.95
The value is the number in the 6th position, and that is 69
U = 69
5.130) P(X>or = 60)
= P(Z>or= 69 - 61.71/8.8)
= P(Z> or = 0.8208)
= 1 - P(Z< or = 0.8209)
= 1 - 0.2942
= 0.7058
Answer:
When the number of guests is 0, the cost would be $450.
Step-by-step explanation:
We have been given an equation 
, which models the relation between the cost in dollars, C, of the banquet and the number of guests, g.
We can see that our given equation in slope-intercept form of equation 
, where, m represents slope of line and b represents y-intercept or initial value.
We can see that slope for our given equation is 28 and the C-intercept is 450.
The C-intercept tells us that when there are 0 guests in the banquet, the cost would be $450.
