Please help with problems 6 and 7.

Please I need help with this I’ve been stuck on this problem for a while now

Genrish500 [490]

Answer:

75% i belive

Step-by-step explanation:

that is the 3 24% ofter 34. that means the answer will be 75%

7 0

2 years ago

Find the lateral area of the regular prism with height h, if the base of the prism is: Equilateral triangle with the side 4 cm a

Shtirlitz [24]

Equilateral triangle with the side 4 cm and h=2.5 cm

In equilateral triangle all sides are equal

so all sides are equal in the base of the prism

lateral area of the prism = Perimeter of the base * height

Perimeter of the base equilateral triangle = side + side + side

lateral area of the prism =(side + side + side) * height

= (4+4+4) * 2.5

= $30 cm^2$

lateral area of the prism = $30 cm^2$

6 0

2 years ago

Read 2 more answers

Only question numer 10.

leva [86]

Out of the six, only “u” wouldn’t work so the answer is d. 5

Hope this helps and hope you have a great day! Please make brainiest

4 0

2 years ago

Read 2 more answers

On the blueprint for Joey's new house,his floor measures 9 square feet.The actual house will have an area of 1296 square feet.Wh

bonufazy [111]

Answer:

1:144 ft²

Step-by-step explanation:

9 : 1296

1 : x

9x = 1296

x = 1296/9

x = 144

Scale factor = 1:144

6 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

2 years ago