We can use this formula to solve for acceleration of the table
F = ma
We are given with the force and the mass, so
6 N = 6 kg a
a = 1 m/s2
The change in velocity can be solve using this formula
FΔt = mΔv
6N (2s) = (6 kg) (Δv)
Δv = 2 m/s
<span>Let's consider a scenario in which the resting membrane potential changes from −70 mV to +70 mV, but the concentrations of all ions in the intracellular and extracellular fluids are unchanged. Predict how this change in membrane potential affects the movement of Na+. The electrical gradient for Na+ would tend to move Na+ Outside the cell (extracellular) while the chemical gradient for Na+ would tend to move Na+ Inside the cell (intracellular).
The electrical gradient is defined as the + goes to the - and the - goes to the +
Na + has a positive charge, but there's more positive charge inside the cell than outside (due to potassium), therefore, Na+ goes extracellular (out)
The concentration gradient considers that the ion will go from the most concentrated to at least concentrated by passive diffusion so no trans-membrane proteins in the game attention.Na + is very concentrated in extracellular and few intracellular, therefore, it tends to go intracellular (in).</span>
Answer:
DNA carries the genetic information for making proteins. ... The base sequence determines amino acid sequence in protein. Messenger RNA (mRNA) is a molecule which carries a copy of the code from the DNA, in the nucleus, to a ribosome, where the protein is assembled from amino acids.
Answer:
Genes are segments of deoxyribonucleic acid (DNA) that contain the code for a specific protein that functions in one or more types of cells in the body. Chromosomes are structures within cells that contain a person's genes. Genes are contained in chromosomes, which are in the cell nucleus.
Hopefully that helped you answer your question
Explanation:
Dad: TtBb
Mom: ttbb
You have to use distribution for dihybrid crosses. Meaning, the first allele of each trait has a equal chance of being paired with the other allele of the other trait. So for example with Dad, I will number the traits:
T(1)t(2)B(3)b(4)
To set up the possibilities from Dad, it would be 13, 14, 23, 24: TB, Tb, tB, tb. Same idea goes for Mom, except since all alleles are the same, you only need to make one column for Mom, since if you did all 4, the other 3 would just be repeats of the 1.
Cross:
tb
TB TtBb
Tb Ttbb
tB ttBb
tb ttbb
The phenotypic ratio is 1 Tall Brown: 1 Tall Blue: 1 Short Brown: 1 Short Blue
