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3 years ago

Someone help and please make sure it’s right :)

Mathematics

1 answer:

Elan Coil [88]3 years ago

7 0

Answer:

Its answer is 55°

hope it will help you..

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The side lengths of a square measure 25.3 cm. Estimate the area of the square.

s2008m [1.1K]

Estimate, ok
area=side^2
if we round
25^2=625
25.3 is slighly bigger so maybe 632 squaer centimters or something

3 0

3 years ago

Am I correct or not???

pentagon [3]

Yes that is correct.Well done!:D

3 0

3 years ago

Brenda+said+that+5/2+divided+by+1/4+equals+10.+how+do+you+know+without+dividing+whether+brenda's+statement+is+reasonable?+justif

Lapatulllka [165]

<span>Brenda would be correct, another way to find the answer would be to use the keep change flip method. Where you keep 5/2 change division to multiplication then flip 4/1. The equation would then be 5/2 * 4/1 then you just multiply straight across 5*4 = 20 and 2*1 equals 2. You end up with 20/2 which reduces to 10</span>

6 0

3 years ago

Rewrite the the expression using as few terms as possible. X^2+5x+4x+20

Effectus [21]

Answer:

x^2 + 9x + 20

Step-by-step explanation:

x^2 + 5x + 4x + 20

x^2 + 9x + 20

all u have to do is combine liked terms

8 0

3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0

3 years ago