I will solve one for you to get you a idea so next u can solve all
To know whether line is tangent toa circle or not we should know that that line is a tangent line of a circle if it intersects circle at single point.
and this will always be perpendicular at radius
so in problem
1)

diameter is given 7.5
and u can see they make a right triangle ABC if that is perpendicular so segment AB is tangent to a circle.
Lets see by applying <span>Pythagorean Theorem
</span>this is method we can say that this is in fact a right triangle

a^2=b^2=c^2
a,b are shorter side c is longer side
(7.5)^2+(8)^2=(17)^2
56.25+64=289
120.25=289
both are not equal so they are not forming right triangle so segment AB is not a tangent line.

5 0

3 years ago

Limited time . 10 points

AfilCa [17]

Answer:

Therefore the value of x is

$x=1\pm\sqrt{19}i$

Step-by-step explanation:

Given:

$x^{2}+20=2x$ which is

$x^{2}-2x+20=0$

To Find:

x = ? using Quadratic Formula

Solution:

For a Quadratic Equation ax² + bx + c = 0 , Formula Method is given as

$x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

On Comparing with above we get

$a=1\\b=-2\\c=20$

Substituting a , b , c in Formula method we get

$x=\dfrac{-(-2)\pm\sqrt{(-2)^{2}-4(1)(20)}}{2\times 1}\\\\x=\dfrac{2\pm\sqrt{-76}}{2}\\\\x=\dfrac{2\pm2\sqrt{19}i}{2}\\Dividing\ by\ 2\ we\ get\\\\x=1 \pm\sqrt{19}i$

Therefore the value of x is

$x=1\pm\sqrt{19}i$

8 0

3 years ago

301 345 305 394 328 317 361 325 310 362 What values of minimum, Q1, median, Q3, and maximum should be used to make a box plot fo

Hunter-Best [27]

First, put the numbers in order...very important
301,305,310,317,325,328,345,361,362,394

minimum (smallest number) = 301
Q1 = 310
Q2 (middle number) = (325 + 328)/2 = 653/2 = 326.5
Q3 = 361
maximum (largest number) = 394

3 0

3 years ago