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bagirrra123 [75]
2 years ago
6

A spaceship traveled 1/2 of a light-year and stopped at a space station. Then it traveled 1/12 of a light-year further to a plan

et. How far did the spaceship travel in all?
Mathematics
1 answer:
liq [111]2 years ago
7 0

Answer: 7/12 a light year I believe

Step-by-step explanation:

So what you do is you make the denominators of 1/2 and 1/12 the same which would be 6/12 and 1/12.

You then add them together and you get 7/12

I am sorry if this isn't right :< this is my 1st answer :>

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olga2289 [7]

Answer:can’t read it

Step-by-step explanation:

Can you take a pic closer to the screen?

7 0
3 years ago
Maria drove from Los Angeles (elevation 330 feet) to Death Valley (elevation –282 feet). What is the difference in elevation bet
motikmotik

Answer:

612 feet

Step-by-step explanation:

LA is located at 330 feet ABOVE SEA LEVEL

Death Valley is located 282 feet BELOW SEA LEVEL

We let the sea level be at 0 (consider a number line).

So,

LA would be at +330 feet

and

Death Valley would be at -282 feet

The elevation change between the two would be the difference:

330 - (-282) = 330 + 282 = 612 feet

The difference in elevation = 612 feet

3 0
2 years ago
Plssss help and please don't scam
BARSIC [14]
I believe the answer is 2783 for 1 a - either
5 0
2 years ago
Which function could be a stretch of the exponential decay
yKpoI14uk [10]

Answer:

(x) = 2(1/6)^x

Step-by-step explanation:

To easily solve this problem, we can graph each option using a graphing calculator, or any equation plotting tool.

Case 1

f(x) = 2(6)^x

Case 2

f(x) = 1/2*(6)^x

Case 3

f(x) = 2(1/6)^x

Case 4

f(x) = 1/2*(1/6)^x

By looking at the pictures below, we can tell that the correct option is

Case 3

f(x) = 2(1/6)^x

Since the stretch is done by a factor of 2

6 0
2 years ago
Xavier and Yolanda both have classes that end at noon and they agree to meet every day after class. They arrive at the coffee sh
Leto [7]

Answer:

\mathbf{ \int_{0}^{10} \int_{y}^{y+45} f(x)g(y)dxdy }

Step-by-step explanation:

Ask yourself, when will Xavier and Yolanda meet??

Firstly, since it is given that Xavier doesn't wait at all, in order for them to meet, Yolanda must arrive before Xavier. This in mathematical terms can be expressed as

Y \leq X

Secondly, Yolanda will wait for only 45 minutes, So Xavier must arrive before that, i.e

X \leq Y+45

Combining both conditions, we obtain

Y \leq X \leq Y+45

If f(x) and g(y) be the density functions for Xavier and Yolanda respectively, the probability of meeting is given by,

\int_{0}^{10} \int_{y}^{y+45} f(x)g(y)dxdy.

6 0
3 years ago
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