Answer:
Explanation:
To find the percentage of cars averaged less than 62 mph calculate the corresponding z-score and use a standard normal cumulative probability table
<u>1. Z-score</u>
![Z-score=\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z-score%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
- x is the specific value of the random variable: 62mph
- μ is the mean of the population: 65mph
- σ is the standard deviation of the population: 5mph
Substitute and calculate
![Z-score=\dfrac{62-65}{5}=-0.600](https://tex.z-dn.net/?f=Z-score%3D%5Cdfrac%7B62-65%7D%7B5%7D%3D-0.600)
<u>2. Use of the table.</u>
The percentage of cars that averaged less than 62mph is given by the area under the curve to the left of z = -0.600.
From a standard normal cumulative probability table, the probability of z being less than -0.600 (which is equal to the probability of z being greater than 0.600) is 0.2743, which is 27.43%.
Thus, the conclusion is that 27.43% of the cars averaged less than 62mph.
The answer is ...
150 this is how you find it
Ok so you 10,000 cars you divide that by 200
That is going to give you 50 groups of 200 and if each 200 cars have 3 cars with a defect you just do 50•3
Which is how you get 150 cats