Answer:
Surface area of square pyramid is computed as follows:
A = a² + a*√(a² + 4h²)
where <em>a</em> is the base length and <em>h</em> is the height.
If a model of the square pyramid is scaled down by a factor of x, then the surface area will be:
A' = (a/x)² + (a/x)*√[(a/x)² + 4(h/x)²]
A' = a²/x² + a/x * √[a²/x² + 4h²/x²]
A' = a²/x² + a/x * √[(a² + 4h²)/x²]
A' = a²/x² + a/x * √(a² + 4h²)/√x²
A' = a²/x² + a/x² * √(a² + 4h²)
A' = 1/x² * [a² + a*√(a² + 4h²)]
A' = 1/x² * A
That is, the surface area will be 1/x² times the original surface area. If h = 25 ft and a = 15 ft:
A = 15² + 15*√(15² + 4(25)²) = 1008.02 ft²
The factor is not mentioned in the question, nevertheless, the area will be 1008.02/factor² ft²
If you want to write an equation for an absolute value function this is the parent function y=a|x-h|+k.
In order to write an equation that is 16.5 units right you would do this:
y=|x-16.5|
If you are moving units left the number -16.5 would become 16.5
Remember when you are moving that the number inside is always the opposite sign of where you are moving
Here is the answer:
y=|x-16.5|
Hope This Helps!
Answer:7.3
Step-by-step explanation:
adjacent =x
Hypotenuse =16
Φ=63
From SOHCAHTOA
CosΦ=adjacent ➗ hypotenuse
Cos63=x ➗ 16
Cross multiply
16 x Cos63=x
16 x 0.4540=x
7.264=x
x=7.264
Nearest tenth x=7.3
Answer:
sec(∠F) =
Step-by-step explanation:
In triangle EFD,
m∠F = 90°
Adjacent side of ∠E = EF = 9 units
Opposite side of ∠E = DF = 40 units
Hypotenuse = DE = 41 units
For secant of ∠E ,
sec(∠E) =
=
Therefore, is the ratio of secant of ∠F.
Answer:
3X-7=93,=3x=86=x=28.67
Step-by-step explanation: