Step-by-step explanation:
It is given that,
Initial speed of the car, u = 40 m/s
Final speed of the car, v = 25 m/s
Time taken, t = 3.5 s
(a) We need to find the magnitude and direction of the car’s acceleration as it slows down. It can be calculated using formula as :
The acceleration is in the opposite direction of motion i.e. west.
(b) Let s is the distance the car travel in the 3.5-s time period. It can be calculated using the third equation of motion as
s = 113.9 meters
Hence, this is the required solution.
Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Answer:
<h3>
aₙ = 8n + 27</h3>
Step-by-step explanation:
29 ÷ 12 = 2.41667
Your answer is 2.4 feet
Y-intercept: 0
Slope: 4
Explanation
Y-intercept is the number without the x which in this case is no number so it’s 0 so that’s where the point in the y axis goes
Slope is rise over run so if the equation is 2y = 8x then we can simplify this by dividing both sides by 2 which would be y = 4x so slope is 4/x. Which is basically 4/1 because the x means over one so up 4 units and to the right once
Hope this helps
