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Vlad [161]
3 years ago
15

Solve for x, Correct to one decimal place where 0°<x<90° Sin2x=0,291​

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

Step-by-step explanation:

Sin2x=0,291​

  1. Sin2x = 2Sinx * Cosx
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If m 2 n, which inequalities must be true? Check all that apply.
anzhelika [568]

Answer:

(a)\ m+ 2.1 > n + 2.1

(b).\ m - (-4) > n - (-4)

(c)\ 9 +m> 6 + n

Step-by-step explanation:

Given

m > n

Required

Select true inequalities

(a)\ m+ 2.1 > n + 2.1

Subtract 2.1 from both sides

m > n

This is true

(b).\ m - (-4) > n - (-4)

Open brackets

m + 4 > n + 4

Subtract 4 from both sides

m > n

(c)\ 9 +m> 6 + n

m> -9+6 + n

m> n-3

This is also true

8 0
3 years ago
Read 2 more answers
The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is
Stells [14]
The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is
<span>B. 288.</span>
5 0
4 years ago
During a science experiment,the temperature of a solution in beaker 1 was 5 degrees below zero. The temperature of a solution in
GaryK [48]
Answer:
5 degrees

Step-by-step explanation:

We are given that during a science experiment
The temperature of a solution in a beaker 15 degrees below zero
The temperature of solution in a beaker 2 was opposite of the temperature in beaker 1
We have to determine the temperature of beaker 2.
It mean temperature of beaker 1 solution=-5 degrees
According to question
Temperature of beaker 2 solution =5 degrees
Hence, the temperature of solution in a beaker 2=5 degrees
7 0
1 year ago
6a_6b+3a+4b pleas help me and cool
Ahat [919]

Answer:

9a - 2b

Step-by-step explanation:

6a - 6b +3a +4b . . . . . . . we assume your _ is supposed to be -

= a(6 +3) +b(-6 +4)

= 9a -2b

8 0
4 years ago
If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?
Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

(C_x,C_y) ----> coordinates of point C

we have that

The horizontal distance AB is equal to

AB_x=10-2=8\ units

The vertical distance AB is equal to

AB_y=10-4=6\ units

Find the horizontal coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_x}{CB_x}=\frac{3}{1}

AC_x=3CB_x----> equation A

AC_x+CB_x=8 ----> equation B

substitute equation A in equation B

3CB_x+CB_x=8

4CB_x=8\\CB_x=2

AC_x=3(2)=6

so

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

C_x=A_x+AC_x=2+6=8

Find the vertical coordinate of point C

we know that

\frac{AC}{CB}=\frac{3}{1}

so

\frac{AC_y}{CB_y}=\frac{3}{1}

AC_y=3CB_y----> equation A

AC_y+CB_y=6 ----> equation B

substitute equation A in equation B

3CB_y+CB_y=6

4CB_y=6\\CB_y=1.5

AC_y=3(1.5)=4.5

so

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

C_y=A_y+AC_y=4+4.5=8.5

therefore

The coordinates of point C are (8,8.5)

5 0
3 years ago
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