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2 years ago

Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two

Mathematics

2 answers:

tester [92]2 years ago

6 0

Answer:

8 and 9

Step-by-step explanation:

because

Rzqust [24]2 years ago

3 0

Answer:

8 cm and 9 cm

Step-by-step explanation:

This is the answer because:

1) The other two sides have to equal somethinng that is bigger than 13.

2) 5 cm + 8 cm = 13 cm, therefore, 5 cm and 8 cm is not the correct answer.

3) 6 cm + 7 cm = 13 cm, therefore, 6 cm and 7 cm is not the correct answer.

4) 7 cm + 2 cm = 9 cm, therefore, 7 cm and 2 cm is not the correct answer.

5) Finally, 8 cm + 9 cm = 17 cm, therefore, it is the correct answer since it has a bigger value than 13.

Hope this helps! :D

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How would I solve this problem in steps pls

gregori [183]

In order to solve for a, we must isolate it. To do this, we should add c to both sides, making a the only term on the left.

Final answer: a=c+d-r

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2 years ago

Need help please what is the answer I have been stuck in this for way to long

natita [175]

Answer:

14 + 16 - 35 = ?

Step-by-step explanation:

do the math and that should be the answer

3 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

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3 years ago

There are 527 students enrolled at school 11% are absent today how many students are absent

trapecia [35]

Answer:

About 58 students are absent today.

Step-by-step explanation:

11%=0.11

0.11*527=57.97

3 0

3 years ago

jerome tries to find the value of the expression 3-6+5 by first applying the communtative property. he rewrites the expression a

slega [8]

The commutative property is a property of <em>addition</em>, not of <em>subtraction</em>. It can work in a subtraction problem if you keep the sign with the number, so you're adding positive and negative numbers.

3 - 6 + 5

= (3) + (-6) + (5)

= (3) + (5) + (-6)

= 3 + 5 - 6

5 0

3 years ago